Answered

Differentiation and integration of functions

syms x; y=(11*x+1)/sqrt(x^2+22); dy=diff(y); ddy=diff(dy); for x=1:3 Dy(x)=double(subs(dy)); DDy(x)=double(subs(dd...

Differentiation and integration of functions

syms x; y=(11*x+1)/sqrt(x^2+22); dy=diff(y); ddy=diff(dy); for x=1:3 Dy(x)=double(subs(dy)); DDy(x)=double(subs(dd...

4 giorni ago | 0

Answered

Interpolation between intersecting curves

f=fit(x1',y1','poly5'); g=fit(x2',y2','poly5'); x=min(x2):.01:max(x2); h=1/4.5*(g(x)-f(x))+f(x);%only good for minimum x-rang...

Interpolation between intersecting curves

f=fit(x1',y1','poly5'); g=fit(x2',y2','poly5'); x=min(x2):.01:max(x2); h=1/4.5*(g(x)-f(x))+f(x);%only good for minimum x-rang...

5 giorni ago | 0

Answered

how to write the expression ((pi*epsilon)/ln((D-r)/r)) in matlab?

Are all the variables arrays of equal size? If so, then you need the element-wise operator. c = (pi*epsilon)./log((D-r)./r);

how to write the expression ((pi*epsilon)/ln((D-r)/r)) in matlab?

Are all the variables arrays of equal size? If so, then you need the element-wise operator. c = (pi*epsilon)./log((D-r)./r);

7 giorni ago | 0

Answered

Trapezodial Method using while loop

f=@(x) sin(x); tol=1e-6; x=linspace(0,pi,2); A=sum(movsum(f(x),2,'Endpoints','discard')/2.*diff(x)); n=2; while abs(2-A)>=t...

Trapezodial Method using while loop

f=@(x) sin(x); tol=1e-6; x=linspace(0,pi,2); A=sum(movsum(f(x),2,'Endpoints','discard')/2.*diff(x)); n=2; while abs(2-A)>=t...

7 giorni ago | 0

Answered

how to reshape the matrix

m =[0 0 1 0 0 1 0 0 1 1 1 1 0 1 1 1 0 1 1 1 1]; a=reshape(m,3,[])';

how to reshape the matrix

m =[0 0 1 0 0 1 0 0 1 1 1 1 0 1 1 1 0 1 1 1 1]; a=reshape(m,3,[])';

7 giorni ago | 1

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Answered

Caesar cryptic function problem.

Assuming c is a double array function coded = caesar(c,n) coded=char(mod(c-32+n,95)+32); end

Caesar cryptic function problem.

Assuming c is a double array function coded = caesar(c,n) coded=char(mod(c-32+n,95)+32); end

7 giorni ago | 0

Answered

How to compare two matrices, row by matrix using the GPU

Not sure if something like this would work for you. arrayfun(@(x)ismember(a,b(x,:)),1:size(b,1),'UniformOutput',false);

How to compare two matrices, row by matrix using the GPU

Not sure if something like this would work for you. arrayfun(@(x)ismember(a,b(x,:)),1:size(b,1),'UniformOutput',false);

8 giorni ago | 0

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Answered

How do i finish the code. I'm not even sure if this is how one would start to run the code

x=randi([-10,10]); while x(end)~=9; x=[x,randi([-10,10])]; end display(x(x>0&mod(x,2)==0));

How do i finish the code. I'm not even sure if this is how one would start to run the code

x=randi([-10,10]); while x(end)~=9; x=[x,randi([-10,10])]; end display(x(x>0&mod(x,2)==0));

13 giorni ago | 0

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Answered

my code wont run. was required to write a code to add charecters an store then in array

function x=AccuSumNet(n) for k=1:length(n) x(k)=sum(n{k}-'0'); end end AccuSumNet({'1234567891011121314151617181920...

my code wont run. was required to write a code to add charecters an store then in array

function x=AccuSumNet(n) for k=1:length(n) x(k)=sum(n{k}-'0'); end end AccuSumNet({'1234567891011121314151617181920...

14 giorni ago | 0

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Answered

How can I code this Newton-Raphson and Secant Methods?

The basic code is as follows. You can do other checks as desired.Your code looked ok, except you don't need symbolic variables a...

How can I code this Newton-Raphson and Secant Methods?

The basic code is as follows. You can do other checks as desired.Your code looked ok, except you don't need symbolic variables a...

15 giorni ago | 1

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Answered

integral with vectoric varying coeficient

Why not do it after computing the integral since it is a constant. fun = @(x)coef_vec*exp(-x.^2).*log(x).^2; q = integral(fun,...

integral with vectoric varying coeficient

Why not do it after computing the integral since it is a constant. fun = @(x)coef_vec*exp(-x.^2).*log(x).^2; q = integral(fun,...

18 giorni ago | 0

Answered

How to write a function ?

y=-sin(x/15)*1000./((x-90).^2+(y-110).^2+60)+sin(x/30)*500./((x-55).^2+(y-55).^2+30)+80./(12+abs(x-15))+60./(12+abs(x-20))+80./(...

How to write a function ?

y=-sin(x/15)*1000./((x-90).^2+(y-110).^2+60)+sin(x/30)*500./((x-55).^2+(y-55).^2+30)+80./(12+abs(x-15))+60./(12+abs(x-20))+80./(...

18 giorni ago | 0

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Answered

mathematical equation into matlab

t = (2*L.^2)./(5*I.^2.*H.^2*sqrt(2*g)).*H^(5/2);%assuming I, L, H are same size arrays and g is scalar

mathematical equation into matlab

t = (2*L.^2)./(5*I.^2.*H.^2*sqrt(2*g)).*H^(5/2);%assuming I, L, H are same size arrays and g is scalar

19 giorni ago | 0

Answered

How to set X&Y axis linear in weibull plot

ax=gca; ax.XScale='linear'; ax.YScale='linear';

How to set X&Y axis linear in weibull plot

ax=gca; ax.XScale='linear'; ax.YScale='linear';

19 giorni ago | 0

Answered

Help me with for loop

a=.1; B=exp(-a*(A-A(1,1)).^2);%comparing all pixels to A(1,1)

Help me with for loop

a=.1; B=exp(-a*(A-A(1,1)).^2);%comparing all pixels to A(1,1)

19 giorni ago | 0

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Answered

Newton Raphson!but with multiple initial values :/

i = 0; x=[0.5,1.5,2.5]; n = 5; f = @(x)x.^4 - 9*x.^3+29*x.^2-39*x+18; df= @(x)4*x.^3 - 27*x.^2 +58*x -39;%functions s...

Newton Raphson!but with multiple initial values :/

i = 0; x=[0.5,1.5,2.5]; n = 5; f = @(x)x.^4 - 9*x.^3+29*x.^2-39*x+18; df= @(x)4*x.^3 - 27*x.^2 +58*x -39;%functions s...

19 giorni ago | 2

Answered

What is the problem with my bisection calculation ?

m=5; k=0.4; g=9.81; G=m*g; f=@(x)x-k*G; x=[0,0]; while f(x(1))*f(x(2))>=0 x(1)=input('Enter the left hand side of in...

What is the problem with my bisection calculation ?

m=5; k=0.4; g=9.81; G=m*g; f=@(x)x-k*G; x=[0,0]; while f(x(1))*f(x(2))>=0 x(1)=input('Enter the left hand side of in...

19 giorni ago | 0

Answered

error using integral function

Looks like you are trying to do numerical integration, then no need for symbolic variables. f=@(x)exp(-x.^2/2); v=integral(f,1...

error using integral function

Looks like you are trying to do numerical integration, then no need for symbolic variables. f=@(x)exp(-x.^2/2); v=integral(f,1...

20 giorni ago | 0

Answered

Plotting random points on a circle

a=2*pi*rand(1,50); b=500*rand(1,50); m=[b.*sin(a);b.*cos(a)];

Plotting random points on a circle

a=2*pi*rand(1,50); b=500*rand(1,50); m=[b.*sin(a);b.*cos(a)];

20 giorni ago | 1

Answered

Newton Raphson Method!!!

function x = newton() x=[0.5,1.5,2.5]; f=[1,-9,29,-39,18]; df=polyder(f); for j= 1:5 x = x - polyval(f,x)./polyval(df,x)...

Newton Raphson Method!!!

function x = newton() x=[0.5,1.5,2.5]; f=[1,-9,29,-39,18]; df=polyder(f); for j= 1:5 x = x - polyval(f,x)./polyval(df,x)...

20 giorni ago | 0

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Answered

Performing calculations on a vector

Using elementwise functions and operators. v.^2; v.*m;%v and m same size v./m;%v and m same size v.^m;%va and m same size ....

Performing calculations on a vector

Using elementwise functions and operators. v.^2; v.*m;%v and m same size v./m;%v and m same size v.^m;%va and m same size ....

20 giorni ago | 0

Answered

I keep getting error Array indices must be positive integers or logical values.

y=linspace(0,50,100); d=50 mu=.3 ybyd=y/d%y/d% uinfi=10;%u infinity value% for alpha=-3:3 u=(uinfi.*(ybyd+((alpha.*yby...

I keep getting error Array indices must be positive integers or logical values.

y=linspace(0,50,100); d=50 mu=.3 ybyd=y/d%y/d% uinfi=10;%u infinity value% for alpha=-3:3 u=(uinfi.*(ybyd+((alpha.*yby...

20 giorni ago | 0

Answered

Create a matrix with only the rows indexed by a multiple of N of another matrix.

x2=x1(1:3:length(x1),:);

Create a matrix with only the rows indexed by a multiple of N of another matrix.

x2=x1(1:3:length(x1),:);

20 giorni ago | 1

| accepted

Answered

help for project please

y=(x>=1&x<=10);%will provide logical vector where x is your input vector

help for project please

y=(x>=1&x<=10);%will provide logical vector where x is your input vector

20 giorni ago | 0

Answered

How to find the saturation point x value

a=abs(diff(y)); xvalSat=x(find(a<1e-5,1));%whatever tolerance you want here (1e-5 or less)

How to find the saturation point x value

a=abs(diff(y)); xvalSat=x(find(a<1e-5,1));%whatever tolerance you want here (1e-5 or less)

21 giorni ago | 1

| accepted