Problem with a slope

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as hz
as hz il 27 Ott 2013
Commentato: Image Analyst il 27 Ott 2013
Hi,
Why does the slope result I get from these two points is opposite?
Code:
clc;
clear;
figure, imshow('pout.tif');
b1 = impoint(gca,[]);
b2 = impoint(gca,[]);
pos1 = getPosition(b1);
x1=pos1(1,1);
y1=pos1(1,2);
pos2 = getPosition(b2);
x2=pos2(1,1);
y2=pos2(1,2);
slope = (y2-y1)/(x2-x1);
plot([x1,x2 ],[y1,y2],'Color','r','LineWidth',2);

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Azzi Abdelmalek
Azzi Abdelmalek il 27 Ott 2013
Maybe you should write
slope = ((y1-y2)/(x2-x1))
You can notice that the origin is not in the left bottom, but in the left top corner. check it with
x1
x2
y1
y2
  1 Commento
Image Analyst
Image Analyst il 27 Ott 2013
The direction can be changed with set(gca,'YDir','reverse'). Or maybe it already is since that's what imshow does. In that case, try set(gca,'YDir','normal').

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