Beginner: Want to graph this formula as a 3d shape
Mostra commenti meno recenti
Hi,
I'm interested in graphing a formula similar to the one below in matlab as a shape. Is this at all possible?
x = [1/(y - z - 0.01)] - {1/[(1/(C+D))-((z + 1)/1000)]}
Assume that variables C and D are constants that require user input.
Thanks
Risposte (2)
Image Analyst
il 11 Dic 2013
You can plot this as a surface doing something like this:
C = 2;
D = 5;
z = -5:5;
y = -5:10;
[yy, zz] = meshgrid(y, z);
x = 1 ./ (yy - zz - 0.01) - 1 ./ (1/(C+D)-(zz + 1)/1000);
surf(x);
Be sure to check the parentheses that I used -- I had to guess at what you meant because yours were messed up.
1 Commento
Image Analyst
il 11 Dic 2013
A, it depends on what they mean. A video is 4D data: x, y, color channel, and time. It can be viewed as a movie. 4D data volumetric data can be viewed as a transparent/translucent volume (with more sophisticated software than MATLAB) If you get to 5D data and higher, you'd probably need to reduce it down to 4D or lower.
Please mask as Accepted if I answered your question.
A
il 11 Dic 2013
0 voti
Categorie
Scopri di più su 2-D and 3-D Plots in Centro assistenza e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!