Beginner: Want to graph this formula as a 3d shape

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A
A il 11 Dic 2013
Commentato: Image Analyst il 11 Dic 2013
Hi,
I'm interested in graphing a formula similar to the one below in matlab as a shape. Is this at all possible?
x = [1/(y - z - 0.01)] - {1/[(1/(C+D))-((z + 1)/1000)]}
Assume that variables C and D are constants that require user input.
Thanks

Risposte (2)

Image Analyst
Image Analyst il 11 Dic 2013
You can plot this as a surface doing something like this:
C = 2;
D = 5;
z = -5:5;
y = -5:10;
[yy, zz] = meshgrid(y, z);
x = 1 ./ (yy - zz - 0.01) - 1 ./ (1/(C+D)-(zz + 1)/1000);
surf(x);
Be sure to check the parentheses that I used -- I had to guess at what you meant because yours were messed up.
  1 Commento
Image Analyst
Image Analyst il 11 Dic 2013
A, it depends on what they mean. A video is 4D data: x, y, color channel, and time. It can be viewed as a movie. 4D data volumetric data can be viewed as a transparent/translucent volume (with more sophisticated software than MATLAB) If you get to 5D data and higher, you'd probably need to reduce it down to 4D or lower.
Please mask as Accepted if I answered your question.

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A
A il 11 Dic 2013
Thanks! That worked.
Just a simple question. Is it theoretically impossible to graph a shape which has more than 3 variables? If it has...
a = -5 to 5; b = -5 to 5; c = -5 to 5; d = -5 to 5;
etc..?

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