How to work on fprintf in fopen?
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Hi team,
I am using following code
[ftxt,msg] = fopen([textpath keyword '_summary.txt' ],'w');
fprintf(ftxt, 'Summary sheet of %12s\n\n', TR);
and i am getting error as
Error using fprintf
Invalid file identifier. Use fopen to generate a valid file identifier.
Please help me solving this problem.
Risposte (1)
Wayne King
il 23 Dic 2013
0 voti
What is msg? That is the system-dependent error message returned by fopen. I'm assuming the value of txt is -1 meaning the fopen() operation did not work.
2 Commenti
Radhika
il 23 Dic 2013
Wayne King
il 23 Dic 2013
I'm afraid you need to provide us with more information than you have given. Are we supposed to know what textpath is or keyword?
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