Creating a matrix with values that increase cyclically

Hello,

I would like to create a matrix with two columns. The rows 1-670 would be 1,1; rows 671-1340 rows would be 1,2; rows 1341-2010 would be 1,3. And this trend would continue through the 670 rows of 1,256. After these rows, the next 670 rows would be 2,1; the next 670 rows would be 2,2; and the next 670 rows would be 2,3. So the trend is that every 670 rows, the second column increases by one. And every 670x256 rows, the first column increases by one and the second column resets at one.

Can someone please help with this? Any hints will be helpful.

Many thanks,

John

Answer 1

[Roger Stafford]

An alternative to that is:

 m = 256;
 n = 670;
 t = (.5:m^2*n-.5)'/n;
 M = [floor(t/m),mod(floor(t),m)]+1;

[John Moseley]

Thank you very much for these very nice, elegant solutions... I believe I need a slight extension of this code. I need the trends to continue until the 670 rows of 238,256. So there should be 238x256x670 rows total.

Thanks again,

John

[Roger Stafford]

 m1 = 238;
 m2 = 256;
 n = 670;

followed by either this:

 M = [reshape(repmat(1:m1,n*m2,1),[],1),...
      reshape(repmat(repmat(1:m2,n,1),1,m1),[],1)];

or this:

 t = (.5:m1*m2*n-.5)'/n;
 M = [floor(t/m2),mod(floor(t),m2)]+1;

[John Moseley]

Perfect. Thanks!

Answer 2

[Roger Stafford]

 M = [reshape(repmat(1:256,670*256,1),[],1),...
      reshape(repmat(repmat(1:256,670,1),1,256),[],1)];