Check for 1 in a array

Hey

I have a 3x20 array, where I want to check if row 2 contains 1. If not it should state a message. I was thinking on a if & else . But I'm not quite sure how to check for the number 1.

Answer 1

[Cedric]

Here is an example:

 A = randi( 10, 3 ,20 )  % Dummy example.
 if any( A(2,:) == 1 )
    fprintf( 'Found at least one 1 on row 2!\n' ) ;
 end

Running it gives:

 >> A
 A =
 Columns 1 through 16
  1   7   5   1   6   1   3  10   7   4   4  10   6   9   4   4
  3   1   2   3   6   9   1   7   5   9   4   9   2   7   6   7
  2   7   4   4   8   4   9   6  10   2  10   2   9   3   8   5

 Columns 17 through 20
  2   6   1   6
  7   8   5  10
  6   2   9   7

 Found at least one 1 on row 2!

[Kasper]

When I run it

if any( FCA(2,:) == 1 );
    fprintf( 'Found at least one 1 on row 2!\n' ) ;
end

i get the message:

Undefined function 'eq' for input arguments of type 'cell'.

Don't have eq anywhere.

edit

I just realized I wrote it wrong. It is a 20x3 matrix, not 3x20. But still get the message

[Cedric]

It is because FCA is not a numeric array, but a cell array [ ref ]. Try to convert it to a numeric array first, i.e.:

 FCA_num = cell2mat( FCA ) ;

and then work with FCA_num.

[Kasper]

I guess I should have provided that information, but row 1 is text. So MatLab gives me:

Error using cell2mat (line 46)
All contents of the input cell array must be of the same data type.

[Cedric]

Then convert just row 2 if it is the only row involved.

 row2 = cell2mat( FCA(2,:) ) ;
 if any( row2 == 1 )
     ...
 end

[Kasper]

That worked!

Thank you!

[Cedric]

My pleasure.