read each line of 3 values of a ( n*3 matrix) as a x,y,z positions

Hi there! Hi have this k =

     1     1     2
     2     1     2
     2     2     2
     n1    n2    n3
     n4    n5    n6
     n7    n8    n9 
     n11   n12   n13
    (...) (...) (...)  
And I want for each line to be read as a position xyz, .
For example:
1st line: x=1, y=1, z=2
Afterwards I want to create a new     2*2*2 matrix of zeros, where the xyz positions that I got above are written with a 1 on the new matrix.
ANy help? I need to solve these asap!
Regards

[André Sousa]

following the same question: This is my full code:

aa=rand(2,2,2)

aa(1,1,1)=5;

aa(2,1,1)=8;

aa(1,2,1)=3;

aa(2,2,1)=3;

aa(1,1,2)=7;

aa(2,1,2)=8; aa(1,2,2)=3;

aa(2,2,2)=3;

dimention_aa=size(aa); aareshaped=reshape(aa,[2,4])

ii=rand(3,1);

ii(1,1)=8;

ii(2,1)=3;

ii(3,1)=7;

 for( l=(ii(1):ii(end)))
 ind_reshaped=find(aareshaped==l)

      [R1, C1, S1]=ind2sub(dimention_aa,find(aareshaped==l)
      k=[R1, C1, S1]
      x1=k(:,1)
      y1=k(:,2)
      z1=k(:,3)
      newMatrix = zeros(dimention_aa)

      for j = 1 : size(k, 1)
         newMatrix( x1(j) , y1(j) ,z1(j)) = 1

      end
     % roi_mat(l,:)=x;
end

%%%%%%%%%%%%%%%%%%%%%%%%%%%% Basically the k matrix(that has lines correspondent to xyz positions) is genereated by

[R1, C1, S1]=ind2sub(dimention_aa,find(aareshaped==l)

k=[R1, C1, S1]

And l is a vector with diferent numbers. How do I do the same procedure to go through every element of the l? The code I wrote above, doesn't work quite well.. Regards

Answer 1

[Image Analyst]

Try this:

k =[...
     1     1     1
     2     1     2
     2     2     2]
x = k(:, 1);
y = k(:, 2);
z = k(:, 3);
newMatrix = zeros(2,2,2);
for j = 1 : size(k, 1)
  % Note: y = row, x = column.
  newMatrix(y(j), x(j) ,z(j)) = 1;
end
newMatrix % Print to command window.

Answer 2

[André Sousa]

Thanks for the quick answer!