Difference between FFT and DFT spectrum! why ?!

Hi every body, can some one help me to understand the reason of difference between the spectrum of the DFT(raw formulas) and FFT which I have implemented via the following code? I am investigating the harmonics up to 9 KHZ for a signal with 50 hz basic frequency and the differences appear mostly in ranges higher than 6 KHz.
I have run this code on a set of samples with 10004 samples which is attached to this post .(just import the variables to matlab and run the code below )
for DFT I have used the formulas in yhe below link : DFT formula
CODE:
%%reading in the samples
wave; %%%a 10004 samples signal with basic frequency of 50 Hz which means 10 complete period of the fundametal wave
%%Normal FFT
wavefft1 = fft(wave);
L=size(wave,1)-1; % removing the mirror side of spectrum
MagSpec1 = abs(wavefft1(1:1801))/(L/2); %%removing the mirror side of the spectrum
% and ranging the domain
%%DFT implementation
f = 49.985004498650405; %%f = 10/(time(10004)-time(1)) we have used 10 because these samples consist of 10 periods of the signal with 50 Hz frequency
Sampling_Fequency = 50000;
N = size (wave,1)
ll = 0;
for k = 0: f/10:180*f;
cplx_val =0;
for x = 1:N
Teta = ((2*pi*k*x)/Sampling_Fequency);
cplx_val = cplx_val+(wave(x,1)*complex(cos(Teta),(-1*sin(Teta))));
end
ll = ll+1;
MagSpec2(ll,1) = (floor((abs(cplx_val)/(N/2))*10^6))/10^6; %%removing the mirror side of the spectrum
% and ranging the domain
end
%%drawing the caomparison plot
set(0,'DefaultFigureVisible','on');
figure;
x1 = (0:1800)*5;
plot(x1,MagSpec1,'r-');hold on;
plot(x1,MagSpec2,'g-');
legend('FFT Normal','DFT');

2 Commenti

Ali you can attach your code and sample image here! It's probably easier for lazy ppl like me.
thanks for your hint. I attached the files.

Accedi per commentare.

 Risposta accettata

Matt J
Matt J il 1 Set 2014
Modificato: Matt J il 1 Set 2014
omega=exp(-(2*pi/N)*(0:N-1));
j=sqrt(-1);
for k=N:-1:1
DFT(k) = ( omega.^(j*(k-1)) )*wave(:);
end

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Ali
il 1 Set 2014

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Ali
il 5 Set 2014

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