Sorting cell array based on distance

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Pelajar UM
Pelajar UM il 18 Ott 2021
Commentato: KSSV il 18 Ott 2021
I have two cell arrays that contain information about the x,y,z coordinates for points in space. These data are random and do not necessarily follow any sequence.
Example of data1:
-512.7269 -223.8000 -256.1018
-509.1519 -223.8000 -263.4274
-512.9410 -223.8000 -256.3643
-508.8008 -223.8000 -263.5808
-521.0831 -223.8000 -263.1835
-520.0226 -223.8000 -259.8741
-505.0888 -223.8000 -251.5124
-504.7663 -223.8000 -251.4452
Example of data2:
-500.2925 -178.0828 -260.5501
-500.3713 -177.7340 -259.0459
-500.4465 -177.1616 -257.6118
-500.5162 -176.3785 -256.2803
-500.5790 -175.4029 -255.0823
-500.6334 -174.2572 -254.0454
-500.6780 -172.9680 -253.1935
-500.7120 -171.5645 -252.5458
I am trying to sort the data so that the nearest points in space appear in the same sequence of rows.
This is how the code looks like so far. It calculates the minimum distance for combination of every 2 points and then sort this distance in an ascending fashion. What is missing is the part that updates 'data1' to follow the same sequence.
data1 = importdata ('nodes.txt')
Xi = data1(:,1);
Yi = data1(:,2);
Zi = data1(:,3);
data2 = importdata ('TT_angleBlock_nodes.csv')
Xt = data2(:,1);
Yt = data2(:,2);
Zt = data2(:,3);
input = [Xi,Yi,Zi];
output= [Xt,Yt,Zt];
for row = 1 : 1:row
deltaX = output(row,1) - input(:,1);
deltaY = output(row,2) - input(:,2);
deltaZ = output(row,3) - input(:,3);
% Pythagorean Theorem
distances = sqrt(deltaX .^2 + deltaY .^ 2 + deltaZ .^ 2);
minDistance(row) = min(distances);
Dist = sort (minDistance);
end

Risposta accettata

KSSV
KSSV il 18 Ott 2021
Read about knnsearch. This will give you the nearest points from a set points for a given point. This will work for you.
  4 Commenti
Pelajar UM
Pelajar UM il 18 Ott 2021
I think I figured it out. This is how it should be (I think):
Idx = knnsearch(input,output);
SortedInput = input (Idx,:);
KSSV
KSSV il 18 Ott 2021
Yes....you got it.

Accedi per commentare.

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