Increasing precision when parsing float values using textread()

Hello,
I am using textread() function to parse text values; I have the following line which works well:
[V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13 V14] = textread(file_1,'%f %f %f %f %f %f %f %f %f %f %f %f %f %f','headerlines',5);
The problem I am facing is that float values in the original text contain 6 digits after decimal point, while textread() returns only 4 digits after the decimal point.
For example:
Original value: -0.785834
Value returned by textread(): -0.7858
Please, suggest how to get the full precision of floats when using textread()
Thanks in advance

1 Commento

Are you sure that the value returned is EXACTLY -0.7858, or is that just what matlab is displaying?

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 Risposta accettata

Stephen23
Stephen23 il 13 Ott 2014
Modificato: Stephen23 il 13 Ott 2014
I just created a new text file containing only the text '0.1234567890123456789', and named it 'temp.txt'. Then I ran this:
>> A = textread('temp.txt','%f');
>> fprintf('%.20f\n',A)
0.12345678901234568000
This shows that textread has read that number up to the double precision limit (~17 sigfig).
The "problem" is likely to be how MATLAB displays numbers up to four decimal digits, much to the confusion of all MATLAB learners, who wonder where their digits have gone to. Don't worry, those digits are still there! Have a look at format for more information on how to change the displaying of numbers.
Also as Adam mentions, the documentation reccomends using textscan instead of textread.

1 Commento

Thanks, indeed the problem was with formatting when displaying the result!

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Più risposte (1)

Adam
Adam il 13 Ott 2014
Modificato: Adam il 13 Ott 2014
The help page (R2014b) suggests you should use textscan now instead of textread, but I assume the following works for either while textread still exists.
You can specify the precision you want for your floats by e.g.
%.6f
to specify the number of values after the decimal place.

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Richiesto:

il 13 Ott 2014

Commentato:

il 13 Ott 2014

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