ASP-N uses incorrect position in Cleave?
    4 visualizzazioni (ultimi 30 giorni)
  
       Mostra commenti meno recenti
    
    Ryan Leib
 il 12 Nov 2014
  
    
    
    
    
    Commentato: Luuk van Oosten
      
 il 24 Nov 2014
            Hi,
Using the cleave() function, ASP-N is stated to cleave at position 2 by cleavelookup(). However, this should be clipping at position 0 (n-terminal of D residues). Can someone else verify this is functioning incorrectly?
0 Commenti
Risposta accettata
  Luuk van Oosten
      
 il 24 Nov 2014
        Dear Ryan,
I am no expert, but I've used the cleave function before to make an in silico tryptic digest and also had some troubles using the MATLAB build-in codes for cleavage; confused me as well.
What I eventually did was use the following (and this is clearly explained in the help docs as well):
you want to use cleave and produce fragments (I presume.... your question lacks a lot of info...)
Fragments = cleave(SeqAA, PeptidePattern, Position)
so, for 'SeqAA' you put in the sequences you want to cleave. For 'PeptidePattern' you would want to use 'D' (cleave at an aspartic acid), and if you specify 'Position' as '0', it would cleave your sequences exactly as you described in your questions;
so:
SeqAA = yoursequences;
PeptidePattern = D;
Position = 0;
yourfragments =  cleave(SeqAA, PeptidePattern, Position)
I guess that would do the job, but you should try it out for yourself; I have no idea what you want to do.
2 Commenti
Più risposte (0)
Vedere anche
Categorie
				Scopri di più su Risk Management Toolbox in Help Center e File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!