How to speed up this code?

I would like fast code to find the index of the closest element of a vector to a scalar. Here's what I am doing now,

someVector = [1 3.5 5 7 9];
someScalar = 4;
iClosest = find(abs(someVector - someScalar) == min(abs(someVector - someScalar)));

The returned index is 2 since the 2nd element is closest to 4. A parent program spends a lot of time on this line according to the profiler. I'd like to know if it can be done faster or if there's a built-in solution.

Answer 1

[Azzi Abdelmalek]

[~,idx]=min(abs(someVector - someScalar))

[K E]

Thanks, knew there was a more elegant way.