parfor error with 3D matrix

Hello everyone,
I am using the parfor loop for the 3D matrix. When I am executing my parfor loop and getting this error "Error: The variable TEST1 in a parfor cannot be classified. See Parallel for Loops in MATLAB, "Overview". I am replacing the zero value with nan in the loop. Any suggestion regarding this. Your help in this regard will be highly appreciated.
data = rand (20,10,10);
data1 = rand (20,10,10);
parfor ii=1:20
ii
for jj=1:10
jj
TEST1 (ii,jj,:) = data(ii,jj,:).*data1 (ii,jj,:);
TEST1 (TEST1==0) = nan;
end
end

 Risposta accettata

Matt J
Matt J il 30 Gen 2022
Move that line outside the loop.
parfor ii=1:20
ii
for jj=1:10
jj
TEST1 (ii,jj,:) = data(ii,jj,:).*data1 (ii,jj,:);
end
end
TEST1 (TEST1==0) = nan;

Più risposte (1)

sunny kant
sunny kant il 31 Gen 2022

0 voti

Thanks you Matt for your suggestion on the code. However, I am applied the same thing, but when I am applying TES1 (TEST1==0) = nan inside the parfor loop in the code, it gives error. Can you suggest me that why it is happing.

3 Commenti

TEST1(TEST1==0) = nan;
inside the parfor loop would be an attempt to have the worker modify all of the variable TEST1, not just the part that is allocated to the loop. You should confine yourself to just the current worker's values
T2 = TEST1(ii,:,:);
T2(T2 == 0) = nan;
TEST1(ii,:,:) = T2;
Matt J
Matt J il 31 Gen 2022
Modificato: Matt J il 31 Gen 2022
Additionally
TEST1 (TEST1==0) = nan;
is an operation that Matlab already does in a fast, parallelized manner without explicit loops. You should reserve parfor only for things that cannot easily be replaced with vectorized expressions.
Matt J
Matt J il 31 Gen 2022
sunny kant's comment moved here
Thanks Walter for explaining me why my code is not working. As you suggested, I appllied for my code, and now it is working. Thanks for your suggestion on my code and clearing my doubts.

Accedi per commentare.

Categorie

Scopri di più su Loops and Conditional Statements in Centro assistenza e File Exchange

Prodotti

Richiesto:

il 30 Gen 2022

Commentato:

il 31 Gen 2022

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by