if loop on array
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ali hassan
il 7 Feb 2022
Commentato: Image Analyst
il 11 Feb 2022
i want to use if loop on a array. let say if i have two arrays:
a=[1 2 3 4 5]
b=[2 3 4 5 6]
now if i want to use if loop such that when any value in array 'a' is 3 and corresponding value in array 'b' is 4,it should print 'ali'.
i tried the following code but it did'nt work.
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if (any(a==3) & b==4)
sprintf('ali')
end
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Image Analyst
il 10 Feb 2022
Your parentheses are not right. Try it this way
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if any(a==3 & b==4)
fprintf('ali\n')
end
A=[1 2 5 66 7];
B=[6 4 4 77 8];
% if any element in array A is 5 and the corresponding B element is between 2 and 6
if any(A==5 & B>=2 & B<=6)
fprintf('ali')
else
fprintf('No Matches.\n')
end
5 Commenti
Image Analyst
il 11 Feb 2022
@ali hassan if you have the Image Processing Toolbox, you can use regionprops():
ff_liter_ho = [nan, 75, 0, nan, nan, nan, nan, nan, nan, nan, 75, 37, nan, 0, 1, 2, 3, 4]
nonZeroIndexes = ff_liter_ho > 0
props = regionprops(nonZeroIndexes, 'Area');
numRuns = length(props)
runLengths = [props.Area]
Più risposte (1)
KSSV
il 7 Feb 2022
a=[3 4 3 44 3];
b=[4 3 4 34 26];
if (any(a==3))
idx = a == 3 ;
if any(b(idx) == 4 )
fprintf('ali\n')
end
end
4 Commenti
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