solution of matrix eigen value equation
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
shiv gaur
il 8 Feb 2022
Risposto: Walter Roberson
il 8 Feb 2022
n1=1.50;
n2=1.746;
n3=0.55-1i*11.5;
n4=1.444;
t1=5;
t2=1:70;
t3=24;
k0=2*pi/1.55;
k1=k0*sqrt(beta^2-n1^2);
k2=k0*sqrt(beta^2-n2^2);
k3=k0*sqrt(beta^2-n3^2);
k4=k0*sqrt(beta^2-n4^2);
M1=1/2(1+(k1/k2)*exp(-k1*t1) (1-(k1/k2)*exp(k1*t1);(1-(k1/k2)*exp(-k1*t1) (1+(k1/k2)*exp(k1*t1) );
M2=1/2(1+(k2/k3)*exp(-k2*t2) (1-(k2/k3)*exp(k2*t2);(1-(k2/k3)*exp(-k2*t2) (1+(k2/k3)*exp(k2*t2) );
M3=1/2(1+(k3/k4)*exp(-k3*t3) (1-(k3/k4)*exp(k3*t3);(1-(k3/k4)*exp(-k3*t3) (1+(k3/k4)*exp(k3*t3) );
M=M3*M2*M1=[m11 m12; m21 m22]
A=(A1;A2);
B=(B1;B2);
A2=0;
B1=0;
A=M*B;
m22(beta)=0;
from this equation plot(t2 vs beta)
2 Commenti
Risposta accettata
Walter Roberson
il 8 Feb 2022
I had to make a bunch of guesses. In particular your M1 M2 M3 were not coded properly, and I had to guess about where to put the ) . I also had to guess about beta.
Eventually I hit the point where you have an equation relating to the undefined variables m11 m12 m21 m22 and I gave up trying to fix at that point.
You do not define A1, A2, B1, B2 before they are used, and you overwrite some of them after they are used which is confusing. You also overwrite A after you define it, which is again confusing.
There is too much wrong with the code for me to be able to fix it at this time.
n1=1.50;
n2=1.746;
n3=0.55-1i*11.5;
n4=1.444;
t1=5;
%t2=1:70;
syms t2 beta
t3=24;
k0=2*pi/1.55;
k1=k0*sqrt(beta^2-n1^2);
k2=k0*sqrt(beta^2-n2^2);
k3=k0*sqrt(beta^2-n3^2);
k4=k0*sqrt(beta^2-n4^2);
M1 = [1/2*(1+(k1/k2))*exp(-k1*t1), (1-(k1/k2)*exp(k1*t1)); (1-(k1/k2)*exp(-k1*t1)), (1+(k1/k2)*exp(k1*t1)) ]
M2 = [1/2*(1+(k2/k3))*exp(-k2*t2), (1-(k2/k3)*exp(k2*t2)); (1-(k2/k3)*exp(-k2*t2)), (1+(k2/k3)*exp(k2*t2)) ]
M3 = [1/2*(1+(k3/k4))*exp(-k3*t3), (1-(k3/k4)*exp(k3*t3)); (1-(k3/k4)*exp(-k3*t3)), (1+(k3/k4)*exp(k3*t3)) ]
M = M3*M2*M1 == [m11 m12; m21 m22]
A = [A1;A2]
B = [B1;B2]
A2 = 0;
B1 = 0;
A = M*B;
eqn = m22*beta == 0
0 Commenti
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!