# how to write summation

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shiv gaur
on 21 Feb 2022

Commented: Walter Roberson
on 24 Feb 2022

pl write in this summation

##### 0 Comments

### Accepted Answer

Walter Roberson
on 24 Feb 2022

offset = 1; % Indices are 1-based in Matlab

S = 0;

for p = 0:i

S = S + A(offset+p) * C(offset + i - p);

end

##### 6 Comments

Walter Roberson
on 24 Feb 2022

### More Answers (1)

Jan
on 23 Feb 2022

S = 0;

for p = 1:i+1 % Indices are 1-based in Matlab

S = S + A(p) + C(i - p);

end

##### 7 Comments

Rik
on 24 Feb 2022

Is your shift key broken? And the keys for the . , and ? symbols? That must be very difficult.

You didn't provide values for A, so apparently those don't matter. Why should Jan pick some numbers to show his code works? You could have done exactly like me: write the example below. Then you could actually show what your problem is. If you can't explain it in English, you should explain it in Matlab.

i=10;

A=rand(i+1,1);

C=rand(size(A));

S = 0;

for p = 1:i+1 % Indices are 1-based in Matlab

S = S + A(p) + C(i - p);

end

And now we can see that Jan made a small mistake: he corrected the indexing of A, but forgot to fix the indexing of C. Walter has now posted an answer that fixes this.

Also, sending me emails will not do anything. You should format your code as code. It isn't hard. Press ctrl-E before you paste any code or use the bar that appears when you write . Using interpunction will also help. If you post code that doesn't run when you click the small run icon, then the problem is not that I haven't seen your research, the problem is that you didn't include all variable definitions. I did not close your question because I was unable to answer your question, I closed it because you seem to be unwilling to use the tools provided to you. If I insisted on answering your questions in a Dutch dialect, you would not be able to understand me and my answer would be useless to you. If you insist on not formatting your posts and not using any interpunction you make your responses almost useless as well.

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