unable to plot this equation

t=1:20;
a(1)=1;
b(1)=1;
c(1)=1;
I=0.5;
a=1;b=3;
c=1;
d=5
r=0.0001;
s=4;
xr=-1.6
sumx=0;
sumy=0;
sumz=0;
for i=1:20
a(i+1)=(-a*a(i).^3+b*a(i).^2+b(i)-c(i)+I)/(i+1)
b(i+1)=(c-d*a(i)^2-b(i))/(i+1);
c(i+1)=r*((s*(a(i)-xr)-c(i)))/(i+1);
sumx=sumx+a(i)*t.^i;
sumy=sumy+b(i).*t.^i;
sumz=sumz+c(i).*t.^i;
end
plot(t,sumx)

4 Commenti

why are using a for loop for indexing ?
all of your variable is a scalar element. Try this code
t=1:20;
I=0.5;
a=1;b=3;
c=1;
d=5;
r=0.0001;
s=4;
xr=-1.6;
sumx=0;
sumy=0;
sumz=0;
for i=1:20
A=(-a*a.^3+b*a.^2+b-c+I)/(i+1);
B=(c-d*a^2-b)/(i+1);
C=r*((s*(a-xr)-c))/(i+1);
sumx=sumx+A*t.^i;
sumy=sumy+B.*t.^i;
sumz=sumz+C.*t.^i;
end
plot(t,sumx)
shiv gaur
shiv gaur il 23 Feb 2022
no a(i) came from derivation of power series this is not avoid
Arif Hoq
Arif Hoq il 23 Feb 2022
so what is the value of a ? it can not be a scalar.here a =1. it should be a vector or matrix
shiv gaur
shiv gaur il 23 Feb 2022
so a is the vector you can take a is the parameter scalar a(i) is the vector so you can take replacement as a=m
for simplicity edit program is here
t=1:20;
a(1)=1;
b(1)=1;
c(1)=1;
I=0.5;
m=1;b=3;
c=1;
d=5
r=0.0001;
s=4;
xr=-1.6
sumx=0;
sumy=0;
sumz=0;
for i=1:20
a(i+1)=(-m*a(i).^3+b*a(i).^2+b(i)-c(i)+I)/(i+1)
b(i+1)=(c-d*a(i)^2-b(i))/(i+1);
c(i+1)=r*((s*(a(i)-xr)-c(i)))/(i+1);
sumx=sumx+a(i)*t.^i;
sumy=sumy+b(i).*t.^i;
sumz=sumz+c(i).*t.^i;
end
plot(t,sumx)

Accedi per commentare.

Risposte (1)

i have considered the variable with random number
t=1:20;
I=0.5;
a=randi(20,1,20);
b=randi(30,1,20);
c=randi(30,1,20);
m=1;
d=5;
r=0.0001;
s=4;
xr=-1.6;
sumx=0;
sumy=0;
sumz=0;
C=cell(1,3);
for i=1:20
C{i,1}=(-m*a(i).^3+b*a(i).^2+b(i)-c(i)+I)/(i+1);
C{i,2}=(c-d*a(i)^2-b(i))/(i+1);
C{i,3}=r*((s*(a(i)-xr)-c(i)))/(i+1);
sumx=sumx+C{i,1}.*t.^i;
sumy=sumy+C{i,2}.*t.^i;
sumz=sumz+C{i,3}.*t.^i;
end
plot(t,sumx)

2 Commenti

shiv gaur
shiv gaur il 23 Feb 2022
so you are req to plot as same value not random value
Arif Hoq
Arif Hoq il 23 Feb 2022
Modificato: Arif Hoq il 23 Feb 2022
do you mean?
a =ones(1,20,1)
a = 1×20
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
b=repmat([2 2 2 2 2],1,4)
b = 1×20
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2
c=repmat([3 3 3 3 3],1,4)
c = 1×20
3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3

Accedi per commentare.

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Release

R2021b

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Richiesto:

il 23 Feb 2022

Modificato:

il 23 Feb 2022

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