time shifting

i want the program to advance or delay the signal... by taking input from user whether to advance or delay & by what number?.... please use switch statement?.... any signal like-ramp,step,exponential in it i am using subplot to plot the original signal & shifted version of the signal..

i have a program something like this--
*clear all
close all
clc
disp('given function is')
x=(-10:10);
for i=1:1:21
if(x(i)>0)
    y(i)=exp(x(i));
else
    y(i)=0;
end
end
subplot(1,2,1)
stem(x,y)
disp('enter whether to advance or delay')
s=input('1>advance\n 2>Delay')
n=input('enter the no of step by which signal is to be shifted')
switch(s)
case 1
    [
     for i=1+n:1:21+n
     if(x(i)>0)
     y(i)=1;
     else
     y(i)=0;
     end
    ]
case 2
    [
     for i=1-n:1:21-n
     if(x(i)>0)
     y(i)=1;
     else
     y(i)=0;
     end
    ]
subplot(1,2,2)
stem(x,y)

but when i run the program it gives error in the 'for' command in case 1.

[Paulo Silva]

What kind of signal and why use switch statement?

usually switch statements are for more complex problems.

[Matt Tearle]

Can you please explain in more detail what you're trying to do? Do you have a time base vector t and a signal y(t) and you want the user to input a dt... and then do... what with it exactly?

[ap singh]

i am begneer to matlab...

so Paulo Silva & Matt if you can help me in some more programs i will be very thankfull to u...

i need code to this programm

tell me the problem in the above program

thxs

Answer 1

[Jan]

Omit the square brackets around the case blocks and close the SWITCH and IF blocks with an END.

switch(s)
case 1
   for i=1+n:1:21+n
     if(x(i)>0)
       y(i)=1;
     else
       y(i)=0;
     end
   end
case 2
   for i=1-n:1:21-n
     if(x(i)>0)
       y(i)=1;
     else
       y(i)=0;
     end
   end
end

[ap singh]

will this program work??

is this right??...

Answer 2

[Sk Group]

Time Shifting in MATLAB (Code + Output)

For detailed post and complete code visit: https://www.swebllc.com/time-shifting-in-matlab-code-output/

Answer 3

[Walter Roberson]

You cannot have an 'if' statement inside of [] . But you don't need to mark the beginning and end of the code for an individual case: all code is executed until the next 'case' or unmatched 'end'.

[ap singh]

ok but but my college sir told me that square [] are to be put so i put them.... now you hav told me to do it without brackets i will try it.. thnks

Answer 4

[Matt Tearle]

On top of the syntax issues Walter and Jan point out...

1. Why use switch? You could easily use a simple if/|else|. But why not just flip the sign of the offset. Something like n = sign(1.5-s)*n

2. You can make the unshifted signal in a couple of lines:

y = exp(x);
y(x<=0) = 0;

3. What you have in the switches will cause an error because it will try to reference x(22) (or higher), but x only has 21 elements. What are you trying to do here? I would have thought that what you want mathematically is y(x+dx). In which case you could repeat the above lines with a shifted x:

x2 = x + dx;
y = exp(x2);
y(x2<=0) = 0;

Also, what you have there sets y to just 0 or 1, rather than 0 or exp(x). Was that what you intended?

[ap singh]

yes sure i can..

but i am learning the use of the SWITCh statement...

Answer 5

[ap singh]

thanks to

Walter Roberson,Matt,Jan Simon,Paulo Silva for commenting & answering to my question!!!.....

meet u 2mmrw

Answer 6

[ap singh]

as Jan Simon remove square brackets

i have written it like

clear all
close all
clc
disp('given function is')
x=(-10:10);
for i=1:1:21
if(x(i)>0)
    y(i)=exp(x(i));
else
    y(i)=0;
end
end
subplot(1,2,1)
stem(x,y)
disp('Enter whether to advance or delay')
s=input('1>advance\n 2>Delay=\n')
n=input('enter the no of step by which signal is to be shifted=')
switch(s)
case 1
     for i=1+n:1:21+n
if(x(i)>0)
    y(i)=exp(x(i));
else
    y(i+n)=0;
end
     end
case 2
     for i=1-n:1:21-n
if(x(i)>0)
    y(i)=exp(x(i));
else
    y(i-n)=0;
end
     end
end
subplot(1,2,2)
stem(x,y)

but still gives error as

" given function is Enter whether to advance or delay 1>advance 2>Delay= 1

s =

     1

enter the no of step by which signal is to be shifted=1

n =

     1

??? Attempted to access x(22); index out of bounds because numel(x)=21.

Error in ==> Untitled2 at 21 if(x(i)>0)"

please help...

[Jan]

Do not access elements out of range:

for i=1+n:1:21+n

==>for i=1+n:min(21+n, length(x))

(a:1:b is the same as a:b)

and

for i=1-n:1:21-n

==>for i=1:21-n

You cannot access x(22) or x(0).

Answer 7

[Saurabh]

clear all

close all

clc

disp('given function is')

x=(-10:10);

for i=1:1:21

if(x(i)>0)

y(i)=exp(x(i));

else

y(i)=0;

end

end

subplot(1,2,1)

stem(x,y)

disp('Enter whether to advance or delay')

s=input('1>advance\n 2>Delay=\n')

n=input('enter the no of step by which signal is to be shifted=')

switch(s)

case 1

for i=1+n:1:21+n

if(x(i)>0)

y(i)=exp(x(i));

else

y(i+n)=0;

end

end

case 2

for i=1-n:1:21-n

if(x(i)>0)

y(i)=exp(x(i));

else

y(i-n)=0;

end

end

end

subplot(1,2,2)

stem(x,y)