optomization using Genetic Algorithm

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% Hi everyone
% I download this function to maximize an objective function using Genetic Algorithm, but I am trying to use it , but I dont know how enter my objectve function to this code. Please could anyone help me
if anyone can choose any function and try to maximize it using this function
function [beta,stopcode]=ga_maximize(funstr,parspace,options)
%[beta,stopcode]=ga(funstr,parspace,options,p1,p2,p3,p4,p5,p6,p7,p8,p9)
% Genetic Algorithm for function maximization.
% Especially useful for functions with kinks and discontinuities,
% and where a good "starting point" is unavailable.
% See Dorsey and Mayer,
% Journal of Business and Economic Statistics, January 1995, 13(1)
% Program by Michael Gordy <m1mbg00@frb.gov>
% Version 1.12, 7 February 1996
%
% OUTPUTS:
% beta = (1 x K) parameter vector maximizing funstr
% stopcode = code for terminating condition
% == 1 if terminated normally
% == 2 if maximum number of iterations exceeded
%
% INPUTS:
% funstr = name of function to be maximized (string).
% parspace = (2 x K) matrix is [min; max] of parameter space dimensions
% or, if (3 x K), then bottom row is a good starting value
% options = vector of option settings
% p1,p2,...,p9 are optional parameters to be passed to funstr
%
% where:
% options(1) = m (size of generation, must be even integer)
% options(2) = eta (crossover rate in (0,1); use Booker's VCO if < 0)
% options(3) = gamma (mutation rate in (0,1))
% options(4) = printcnt (print status once every printcnt iterations)
% Set printcnt to zero to suppress printout.
% options(5) = maxiter (maximum number of iterations)
% options(6) = stopiter (minimum number of gains < epsln before stop)
% options(7) = epsln (smallest gain worth recognizing)
% options(8) = rplcbest (every rplcbest iterations, insert best-so-far)
% options(9) = 1 if function is vectorized (i.e., if the function
% can simultaneously evaluate many parameter vectors).
% Default option settings: [20,-1,0.12,10,20000,2000,1e-4,50,0]
%
% Note:
% The function is maximized with respect to its first parameter,
% which is expressed as a row vector.
% Example:
% Say we want to maximize function f with respect to vector p,
% and need also to pass to f data matrices x,y,z. Then,
% write the function f so it is called as f(p,x,y,z). GA will
% assume that p is a row vector.
gaver='1.12';
defopt=[24,-1,0.12,10,20000,2000,1e-4,50,0];
months = ['Jan';'Feb';'Mar';'Apr';'May';'Jun';...
'Jul';'Aug';'Sep';'Oct';'Nov';'Dec'];
if nargin>2
if isempty(options)
options=defopt;
end
else
options=defopt;
end
m=options(1); eta=options(2); gam=options(3);
printcnt=options(4);
maxiter=options(5);
stopiter=options(6); epsln=options(7);
rplcbest=options(8);
vecfun=options(9);
% Use Booker's VCO if eta==-1
vco=(eta<0); eta=abs(eta);
% Cancel rplcbest if <=0
if rplcbest<=0, rplcbest=maxiter+1; end
K=size(parspace,2);
% Draw initial Generation
G=rand(m,K).*(parspace(2*ones(m,1),:)-parspace(ones(m,1),:))...
+parspace(ones(m,1),:);
b0rows=size(parspace,1)-2;
if b0rows>0
G(1:b0rows,:)=parspace(3:b0rows+2,:);
parspace=parspace([1 2],:);
end
% Initial 'best' holders
inarow=0;
bestfun=-Inf; beta=zeros(1,K);
% Score for each of m vectors
f=zeros(m,1);
% Setup function string for evaluations
paramstr=',p1,p2,p3,p4,p5,p6,p7,p8,p9';
evalstr = [funstr,'(G'];
if ~vecfun
evalstr=[evalstr, '(i,:)'];
end
if nargin>3, evalstr=[evalstr,paramstr(1:3*(nargin-3))]; end
evalstr = [evalstr, ')'];
% Print header
if printcnt>0
disp(['GA (Genetic Algorithm), Version ',gaver,' by Michael Gordy'])
disp(['Maximization of function ',funstr])
disp('i = Current generation')
disp('best_i = Best function value in generation i')
disp('best = Best function value so far')
disp('miss = Number of generations since last hit')
disp('psi = Proportion of unique genomes in generation')
disp(sprintf(['\n',blanks(20),'i best_i best miss psi']))
end
iter=0; stopcode=0;
oldpsi=1; % for VCO option
while stopcode==0
iter=iter+1;
% Call function for each vector in G
if vecfun
f=eval(evalstr);
else
for i=1:m
f(i)=eval(evalstr);
end
end
f0=f;
[bf0,bx]=max(f);
bf=max([bf0 bestfun]);
fgain=(bf-bestfun);
if fgain>epsln
inarow=0;
else
inarow=inarow+1;
end
if fgain>0
bestfun=bf;
beta=G(bx(1),:);
end
if printcnt>0 & rem(iter,printcnt)==1
psi=length(unique(G))/m;
ck=clock;
ckhr=int2str(ck(4)+100); ckday=int2str(ck(3)+100);
ckmin=int2str(ck(5)+100); cksec=int2str(ck(6)+100);
timestamp=[ckday(2:3),months(ck(2),:),' ',...
ckhr(2:3),':',ckmin(2:3),':',cksec(2:3),' '];
disp([timestamp,sprintf('%6.0f %8.5e %8.5e %5.0f %5.3f',...
[iter bf0 bestfun inarow psi])])
save gabest beta timestamp iter funstr
end
% Reproduction
f=(f-min(f)).^(1+log(iter)/100);
pcum=cumsum(f)/sum(f);
r=rand(1,m); r=sum(r(ones(m,1),:)>pcum(:,ones(1,m)))+1;
G=G(r,:);
% Crossover
if vco
psi=length(unique(G))/m;
eta=max([0.2 min([1,eta-psi+oldpsi])]);
oldpsi=psi;
end
y=sum(rand(m/2,1)<eta);
if y>0
% choose crossover point
x=floor(rand(y,1)*(K-1))+1;
for i=1:y
tmp=G(i,x(i)+1:K);
G(i,x(i)+1:K)=G(i+m/2,x(i)+1:K);
G(i+m/2,x(i)+1:K)=tmp;
end
end
% Mutation
M=rand(m,K).*(parspace(2*ones(m,1),:)-parspace(ones(m,1),:))...
+parspace(ones(m,1),:);
domuta=find(rand(m,K)<gam);
G(domuta)=M(domuta);
% Once every rplcbest iterations, re-insert best beta
if rem(iter,rplcbest)==0
G(m,:)=beta;
end
stopcode=(inarow>stopiter)+2*(iter>maxiter);
end
if printcnt>0
if stopcode==1
disp(sprintf('GA: No improvement in %5.0f generations.\n',stopiter))
else
disp(sprintf('GA: Maximum number of iterations exceeded.\n'))
end
end

Accepted Answer

Walter Roberson
Walter Roberson on 3 Mar 2022
The function needs to be specified as a character vector that is the name of the function to use. The function named must have its own .m file or be built in: it cannot be a local function or nested function in the same file I think (I would have to test that to be sure.)
The way that the code uses the function is inefficient. The code could be improved.
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