how to calculate cauchy product in summation

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shiv gaur
shiv gaur on 4 Mar 2022
Edited: Jan on 4 Mar 2022
a(1)=1;
b(1)=1;
c(1)=1;
S=0;
Z=0;
for i=1:20
for p=1:i-1
a(i+1)=(1/(i+1)).*(a(i)-b(i));
b(i+1)=(1/(i+1)).*(a(i)-S-b(i));
c(i+1)=(1/(i+1))*(Z-c(i));
S=S+a(p)*c(i-p);
Z=Z+a(p)*b(i-p);
disp([S Z])
end
end
S ,Z are cauchy product how to calculate
  2 Comments
shiv gaur
shiv gaur on 4 Mar 2022
I am not able to calculate the value the value od S and Z inside the loop which is dependent on the equation of a(i) b(i) and c(i) solve the problem this is new problem

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Answers (1)

Jan
Jan on 4 Mar 2022
The shown code cannot run. In the 1st iteration of the "for i" loop, the inner loop is not entered: "for p = 1:i-1". In the 2nd iteration i=2 the innerloop is entered and in the line
a(i+1)=(1/(i+1)).*(a(i)-b(i));
% ^^^ ^^^
The not existing elements a(2) and b(2) are requested.
Seeing only the failing code does not allow to suggest an improvement, because the readers have no chance to guess, what you want to do instead.
  3 Comments
Jan
Jan on 4 Mar 2022
@shiv gaur: You have been asked repeatedly to use a proper code formatting. Please read an consider this: https://www.mathworks.com/matlabcentral/answers/help/rtc#rtc_summary . Thanks.
"pl see the runing program" - the code still stops with an error and we still cannot guess, what it should calculate.
"Resolve the problem" is not a polite way to ask for help, but a rough command. Refusing to post your code in a formatted way and posting not running code repeatedly let it look, like it is your intention to provoke the community.

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