splitting a cell array and determining its size

Imagine that you have a cell array and you want to determine its size. What command would you use for it? Also how do I split the data of the cell array into half. lets say it has 60 rows and and i want it to be split after 30 rows.

thanks

Answer 1

[Guillaume]

Funnily enough. size is the function to get the size of cell arrays and matrices. If you want to split along rows, either use size or end:

c = num2cell(randi(200, 60, 5));
tophalf = c(1: ceil(end / 2), :); %equivalent to c(1 : ceil(size(c, 1) / 2), :)
bottomhalf = c(ceil(end / 2) + 1 : end, :);

[AA]

thanks, I mean size as in bytes.

Also your code is easy to understand. If I have 60 rows and I want the tophalf to be 4 rows and the bottomhalf to be 56 rows then how do i implement these changes? thanks

[Guillaume]

To get the memory footprint of a variable it's whos

c = num2cell(randi(200, 60, 5));
msize = whos('c')

As for splitting:

tophalf = c(1:4, :);
bottomhalf = c(end-56+1:end, :);

[Image Analyst]

That's a funny definition of "half".