Convert a function into a matrix

I want (h(t)) to be in form of matrix, how to do it?
Parameters= {'R0','R1','C1','Qr','bo','b1','SOC','Vrc','Voc'};
R0=0.000605797;
Qr=147964.8608;
R1=0.000856205;
C1=0.049823238;
% X=[SOC;Vrc];
A=[0 0;0 -1/R1*C1];
B=[1/Qr;1/C1];
C=[1 1];
D= R0;
% u=Il;
sys= ss(A,B,C,D);
tfsys = tf(sys);
n = tfsys.Numerator;
d = tfsys.Denominator;
syms s t
H(s) = poly2sym(n,s) / poly2sym(d,s)
H = vpa(H, 5);
h(t) = ilaplace(H)
h = vpa(h, 5)
figure
fplot(h)
grid
axis([0 0.1 0 20])

Risposte (1)

Parameters= {'R0','R1','C1','Qr','bo','b1','SOC','Vrc','Voc'};
R0=0.000605797;
Qr=147964.8608;
R1=0.000856205;
C1=0.049823238;
% X=[SOC;Vrc];
A=[0 0;0 -1/R1*C1];
B=[1/Qr;1/C1];
C=[1 1];
D= R0;
% u=Il;
sys= ss(A,B,C,D);
tfsys = tf(sys);
n = tfsys.Numerator;
d = tfsys.Denominator;
syms s t
H(s) = poly2sym(n,s) / poly2sym(d,s)
H(s) = 
H = vpa(H, 5);
h(t) = ilaplace(H)
h(t) = 
% h = vpa(h, 5)
figure
fplot(h)
grid
axis([0 0.1 0 20])
t1=linspace(0, 0.1, 21)
t1 = 1×21
0 0.0050 0.0100 0.0150 0.0200 0.0250 0.0300 0.0350 0.0400 0.0450 0.0500 0.0550 0.0600 0.0650 0.0700 0.0750 0.0800 0.0850 0.0900 0.0950 0.1000
h1 = double(h(t1))
h1 = 1×21
Inf 15.0041 11.2163 8.3847 6.2680 4.6857 3.5028 2.6185 1.9575 1.4633 1.0939 0.8177 0.6113 0.4570 0.3416 0.2554 0.1909 0.1427 0.1067 0.0798 0.0596

7 Commenti

Can I have the matrix of h(t) without substituting the value of t?
Chunru
Chunru il 24 Giu 2022
Without substituting t, h(t) is a symbolic function rather than a matrix.
I can't understand.. I can convert it into a matrix? because each term represent a term for me so I want it to be in a matrix form in order to see what are the terms
how to convert this symbolic function into a matrix?
Chunru
Chunru il 24 Giu 2022
Can you explain what you want to store in the matrix? What is tge tern you are referring to? Show some examples.
The H(s) function in the code is supposed to be two terms, the state of charge (SOC) and voltage drop (Vrc), but I dont know which terms they are, so I want it to be converted in to a matrix 2x1 in order to identify which terms
Chunru
Chunru il 24 Giu 2022
????????????????????

Accedi per commentare.

Prodotti

Release

R2019b

Richiesto:

il 24 Giu 2022

Commentato:

il 24 Giu 2022

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