How do I plot A=sin(pi*y/2)i - sin(pi*x/2)j using QUIVER
Mostra commenti meno recenti
How do I plot A=sin(pi*y/2)i - sin(pi*x/2)j (where i unit vector in x, j unit vector in y, A resultant vector. x range +/-0.5 ; y range +/-0.5 ). using QUIVER.
Risposta accettata
the cyclist
il 7 Ott 2011
x = -0.5:0.05:0.5;
y = -0.5:0.05:0.5;
[xx,yy] = meshgrid(x,y);
Ai = sin(pi*yy/2);
Aj = - sin(pi*xx/2);
quiver(xx,yy,Ai,Aj)
Più risposte (0)
Categorie
Scopri di più su Vector Fields in Centro assistenza e File Exchange
il 7 Ott 2011
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
