how to plot different figures from the same matrix

Hi!

I have a matrix with 1376x3 dimensions. First column is the day, second the time and third my measurements. The matrix is:

 8  7.56  316
 8  8.45  319.56
 8  10.78 317.4
 9  12.76 323.98
 9  14.27 356.89
 10 13.45 346.12
 10 14.2  312.43

and so on, until the day 365. (some days are missing).

I want to plot the second and third columns for each day separately.

Any ideas?

Thank you!

[Geoff Hayes]

Thodoris - do you want all of this data on one figure or do you want one figure for each day of the year? I can't imagine you wanting up to 365 figures for all of this data so please describe what you would like to obtain and what you have attempted so far.

[Thar]

I want one figure for each day of the year. But i can't separate and keep the data for each day.

Answer 1

[the cyclist]

Try this

D = [
 8  7.56  316
 8  8.45  319.56
 8  10.78 317.4
 9  12.76 323.98
 9  14.27 356.89
 10 13.45 346.12
 10 14.2  312.43]

uniqueDays = unique(D(:,1));
numberUniqueDays = numel(uniqueDays);

for nd = 1:numberUniqueDays
    indexToThisDay = D(:,1)==uniqueDays(nd);
    figure
    plot(D(indexToThisDay,2),D(indexToThisDay,3))
end

[Thar]

Is there way to write the number of the day on the graph?

Thank you!

[Konstantinos Sofos]

use after plot...

title(num2str(uniqueDays(nd)))

Answer 2

[Konstantinos Sofos]

Hi Thodoris,

As i understood in each day you (may) have more that one timestamps of measurements and you want a figure (or plot??) for each corresponding day with its measurements. So i imagine that your basic problem is an indexation problem. (Are your days format as you described i.e. 1,2,3... or in a date number format?)

Assuming the matrix that you gave us

A =

      8.0000    7.5600  316.0000
      8.0000    8.4500  319.5600
      8.0000   10.7800  317.4000
      9.0000   12.7600  323.9800
      9.0000   14.2700  356.8900
     10.0000   13.4500  346.1200
     10.0000   14.2000  312.4300

you can find the indexation of the days as

    idx=find(diff(A(:,1)) == 1) + 1; % day indexation
    idx = [1;idx;length(A)]; % consider the start and the end of the time period

    %plotting : Create a figure for each day

    for i=1:numel(idx)-1
     figure
     x = A(idx(i):idx(i+1)-1,2);
     y = A(idx(i):idx(i+1)-1,3);
     plot(x,y,'r*-')
    end

So this will give you 365 figures...is this really that you want?

Regards