regarding files from directory

I have 156 different files in one folder , out of which I need to read first 13 files only and then start reading from 14 to 26 so on till 156. e.g v_1970_ch4.nc v_1970_ch4_1.nc v_1970_ch4_2.nc . .
v_1970_ch4_13.nc
v_1980_ch4_1.nc v_1980_ch4_1.nc v_1980_ch4_2.nc . .
v_1980_ch4_13.nc
I need to add data together for every 13 files, so how I can set for loop ?
[Edit: moved code from comment]
dir_list =dir('v41_CH4*');
k=0;
for i=1:length(dir_list)
vec1=zeros(720,360);
for j =1:13
k=k+1;
ncid=netcdf.open(dir_list(k).name,'NOWRITE');
latid=netcdf.inqVarID(ncid,'lat');
latitude=double(netcdf.getVar(ncid,latid));
lonid=netcdf.inqVarID(ncid,'lon');
longitude=double(netcdf.getVar(ncid,lonid));
emi_ch4id=netcdf.inqVarID(ncid,'emi_ch4');
ch4=double(netcdf.getVar(ncid,emi_ch4id));
vec1=(vec1+ch4);
end
end

1 Commento

Jan
Jan il 19 Ott 2011
It is always a good idea to post, what you have done so far. Then we can re-use as much code as possible and do not confuse you by using different names for variables etc.

Risposte (1)

Jan
Jan il 19 Ott 2011
Does alphabetical sorting create the wanted order? Or are there problems like in:
sort({'1', '2', '9', '10', '11'})
>> '1' '10' '11' '2' '9'

1 Commento

Uday
Uday il 19 Ott 2011
I think in this case alphabetical order will not work because every time I need to read 1:13 and then 14:26.......156

Questa domanda è chiusa.

Tag

Richiesto:

il 19 Ott 2011

Chiuso:

il 20 Ago 2021

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