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# fzero: not a valid initial bracketing

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Pedro Almeida il 11 Dic 2022
Chiuso: Walter Roberson il 12 Dic 2022
format long
y = @(x) 1 - sin(x);
z = @(x) x.^2;
test1 = @(x) (y(x)-z(x));
test2 = @(x) (z(x) - y(x));
ta = 0;
a = 0;
zero = fzero(test1,[0 1])
while (ta != 1)
a = a + 1;
y1 = @(x) (a - sin(x));
funcao = @(x) (y1(x) - z(x));
intervalo = [0+a 1+a];
ta = fzero(funcao, intervalo);
if (ta = 1)
endif
endwhile
It gives me that error and I don't really know how to fix it. Any help would me appreciated!!
##### 1 CommentoMostra -1 commenti meno recentiNascondi -1 commenti meno recenti
Torsten il 12 Dic 2022
Modificato: Torsten il 12 Dic 2022
Your code is weird and in part not MATLAB compatible:
while / endwhile does not exist in MATLAB; it's while / end
ta != 1 has to be replaced by ta ~= 1
if (ta = 1) has to be replaced by if ta==1
Maybe you should explain in your own words what you try to do.
The error message means that the interval you provided as initial guess for fzero does not satisfy that the function, applied to the endpoints of this interval, gives values that differ in sign.

R2022b

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