Can someone please check my code?

Here are the instructions : The purpose of this assignment is to demonstrate these MATLAB skills:

a. Code a function

b. Code a for loop that sums the terms of a series.

c. Use a conditional statement to break the loop

d. Display the sum after the for loop ends.

Part 1A: Code a Matlab function file called fcn1.m

This loop will sum the terms of a sequence.

The function’s inputs are:

b = a constant used in the calculations.

loop_limit = the value to break for loop.

The function’s output is:

total = the sum of the terms.

Part 1B: Inside this function:

Initialize total = 0;

Initialize term = zeros(1, 100);

Code a for loop with k = 1 to 100 that does the following:

a. Computes term(k) = pi/(12+ k^b);

b Adds term(k) to total. (This will be the sum of all the terms.)

c. Breaks the loop when the absolute value of term(k) is less than loop_limit

Part 2A : Create a Matlab test file that sets these parameters and calls your function:

b = 3;

loop_limit = 0.001

Part 2B:

In the test file, after the call to your function, use the disp() and num2str() functions to display the sum of the series.

Here is the function

function [total] = fcn1(x)
b = 3;
loop_limit = 0.001
total = 0;
  term = zeros(1, 100);
  for k = 1:100
      term(k) = pi/(12+ k^b);
      total = total + term(k);
      if (term(k) < loop_limit) 
          break
      end
  end
end

The calling function

clc; close all; clear all;
y = fcn1(1)
disp(num2str(y))

Thank you so much.

[Eduardo Gallegos]

I made an adjustment to the code.

function

function [total] = fcn1(b,loop_limit)
total = 0;
  term = zeros(1, 100);
  for k = 1:100
      term(k) = pi/(12+ k^b);
      total = total + term(k);
      if (term(k) < loop_limit) 
          break
      end
  end
end

Calling Function

clc; close all; 
y = fcn1(3,0.001);
disp(num2str(y))

Answer 1

[Nikhil]

Hey Eduardo, you have covered all the required aspects in your code. It looks fine.