Turning a complex function into 3d graph

11 visualizzazioni (ultimi 30 giorni)
Beyza Nur
Beyza Nur il 15 Gen 2023
Commentato: Beyza Nur il 15 Gen 2023
Ran in:
lambda= 0.1;
k= 2.*pi./lambda;
theta= 0:.01:2.*pi;
b= 4.*lambda;
r= 6.*lambda;
z= r.*cos(theta);
rho= r.*sin(theta);
f= (exp(-j.*k.*(z-(j.*b)))./(z-(j.*b)).*exp(j.*k.*sqrt(rho)./2.*(z-(j.*b)))).'
f =
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this is the function and I use a few method for 3D graph but I can't get enough result for my project. I think someting is missing. I don't like my results. I used meshgrid and surf command but results not good. Can anyone help me this one? Thank you.
  9 Commenti
Mostra 7 commenti meno recenti
Torsten
Torsten il 15 Gen 2023
Modificato: Torsten il 15 Gen 2023
Ran in:
lambda= 0.1;
k= 2*pi/lambda;
theta= 0:.01:2*pi;
b= 4*lambda;
r= 6*lambda;
z= r*cos(theta);
rho= (r*sin(theta)).';
f= exp(-j.*k.*(z-(j.*b)))./(z-(j.*b)).*exp(j.*k.*sqrt(rho)./2.*(z-(j.*b)));
surf(z,rho,abs(f),"edgecolor","none")
Beyza Nur
Beyza Nur il 15 Gen 2023
okey, thank you for your concern. If I get different information I will update this question.

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