Create a random Matrix

I have a 8 column vector n*1. Can I create a Random matrix of n*8?

The function must take one value from each vector and create a matrix with 8 columns and n rows.

Please help me :-)

[Jan]

"I have a 8 column vector" sounds like a single vector. But "from each vector" might mean n vectors. Confusing.

[Maurizio]

I have 8 different variable. Each variable is a column vector (nx1).

What I need is to have as OUT a random matrix with 8 column and n rows. The value on the first OUT Column must be only the value of the first IN column

Answer 1

[Andrei Bobrov]

A1,A2,..,A8 - your vectors (nx1), let n = 5;

for j1 = 1:8, eval([sprintf('A%d',j1),'=randi(20,5,1)']); end

A = eval(['[',sprintf('A%d,',1:8),']'])
out=A(bsxfun(@plus,cell2mat(arrayfun(@(x)randperm(n)',(1:8),'un',0)),(0:7)*n))

[Maurizio]

Thanks andrei, the problem that the OUT columns value on each columns must be the same of the IN columns. For example the values that I have on the third OUT column must be one of the third IN column.

[Jan]

@Maurizio: Accepting an answer means, that it solves your problem sufficiently.

[Maurizio]

@JAN: I accept but because create a random Matrix but as you can see from my comment Is that there was some problem about OUT columns values

Answer 2

[Walter Roberson]

rv(:,1) = randomvector1;
rv(:,2) = randomvector2;
rv(:,3) = randomvector3;
....
rv(:,4) = randomvector4;

rants = zeros(8, n);
for K = 1:n
  rants(:,K) = A Random Selection of One Entry Per Column from rv
end

How to do "A Random Selection of One Entry Per Column from rv" is left to you to work on in more detail. I will hint that it involves using rand().

[Maurizio]

Can you help me what I need to write on the for loop please?

[Maurizio]

Can you help me what I need to write on the for loop please?

[Walter Roberson]

floor(1 + n * rand())

will give you a random row number.

If I say much more than I will be completing your assignment for you.