I am MATLAB beginner, and I got stuck because of some error.
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Yojp21
il 26 Apr 2023
Commentato: Stephen23
il 26 Apr 2023
I am MATLAB beginner, and I got stuck because of some error.
Error: File: Function1.m Line: 31 Column: 8 (which is very bottom like If R > = Threshold)
Unsupported use of the '=' operator. To compare values for equality, use '=='. To specify name-value arguments, check that name is a
valid identifier with no surrounding quotes.
Also, the End line got an error, too
Line 34: The End operator must be used within an array index expression
How can I fix the errors?
Also, I'm working on an assignment.
If there are mistakes, please let me know/
Task: write a Matlab function that should filter an image to identify the edges and their
orientations (hortizontal, vertical, 45 degree, and 135 degree edges).
Label = 1 for horizontal edges
Label = 2 for vertical edges
Label = 3 for 45 degree edges
Label = 4 for 135 degree (that is -45 degree) edges
Label = 5 for non-edge pixels, i.e. magnitude/response of edge is below a giventhreshold
1. Input: an original image f and a threshold value T;
Output: EdgeImg and IndexImg
2. Pick the four spatial masks H, V, D45, D135 from Note 7 part 1
3. Compute R1 (hortizontal edge), R2 (vertical edge), R3 (45 degree), R4 (135 degree) for the entire image. Hint: use ‘imfilter’. For example:
R1 = imf ilter(f, H)
4. For a pixel at a location (i, j) in the image (you might want to use for loop twice):
(a)
decide in which edge direction the pixel is associated with. For example, if|R2| > Rj for all j = 1, 3, 4, then the pixel is associated with a vertical line. Hint: use [R, ind] = max [R1(i, j), R2(i, j), R3(i, j), R4(i, j)] where R stores the largest response value, ind stores the index/label that is
associated with R.
(b) If the response R ≥ T, then EdgeImg(i, j) = R; IndexImg(i, j) = ind;
(c) If the response R < T, then EdgeImg(i, j) = 0; IndexImg(i, j) = 5; (which is the non-edge index)
Test your function with an image and a threshold value and display both the edge imageand the indexed image.
here is my code
function [EdgeImg, IndexImg] = Function1(InputImg, Threshold)
% Four masks for the entire image
H = [-1 -1 -1; 2 2 2; -1 -1 -1];
V = H';
D45 = [2 -1 -1; -1 2 -1; -1 -1 2];
D135 = [-1 -1 2; -1 2 -1; 2 -1 -1];
% Compute edge strengths and orientations using the four masks
R1 = imfilter(InputImg, H, 'symmetric');
R2 = imfilter(InputImg, V, 'symmetric');
R3 = imfilter(InputImg, D45, 'symmetric');
R4 = imfilter(InputImg, D135, 'symmetric');
%Initial Edgelmg and Indexlmh
EdgeImg=zero(size(InputImg));
IndexImg=len*ones(size(InpuImg));
%Now, loop applied through the pixels at edge using for
for k=1:s(Intlmg,1)
for m =1:s(Intlmg,2)
end
EdgeImg(IndxImg==len)=0;
figure;
subplot(1,2,1,0);
show(EdgeImg,img);
subplot(1,2,2,0);
show(IndexeImg,img);
end
[R,jip] = maximize([R1(k,m),R2(k,m),R3(k,m),R4(k,m)
If R > = Threshold
EdgeImg(k,m)=R;
IndexImg(k,m)=jip;
end
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Risposta accettata
Garrett Fullerton
il 26 Apr 2023
Hey! A greater than/equal to comparison in MATLAB is done using the ">=" symbol. Your code has a space in between the ">" and "=" symbols, and MATLAB is returning an error because it's interpreting the two symbols separately. I would try removing the space and see if that solves your error.
If R >= Threshold
EdgeImg(k,m)=R;
IndexImg(k,m)=jip;
end
3 Commenti
Stephen23
il 26 Apr 2023
"I have no idea what it means"
How are you calling the function? How many input arguments did you provide when you called it?
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