Azzera filtri
Azzera filtri

Solving a PDE using PDE Toolbox

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Tony Stianchie
Tony Stianchie il 6 Mag 2023
Commentato: Tony Stianchie il 6 Mag 2023
This problem invoves an inner pipe with a constant wall temp, an annular space with conduction only, and an insulated outer pipe (no heat transfer)
I'm trying to solve the following Partial Differental Equation as my Governing Equation:
Initial Condition:
@ t = 0s, T = 573 K (uniformly distributed)
Boundary Conditions:
@ r = ri, T = 673 K (constant)
@ r = ro, dT/dr = 0 (insulated end)
This is my first time using pdepe, any help would be appreciated.
I'd like to be able to plot (Temperature vs time) for varying points between the inner and outer radii.

Risposta accettata

Torsten
Torsten il 6 Mag 2023
Modificato: Torsten il 6 Mag 2023
C.ri = 0.0125;
C.ro = 0.0375;
C.alpha = 1.905*10^-5;
C.Ti = 673;
C.T0 = 573;
r = linspace(C.ri,C.ro,50);
t = linspace(0,2000,2001);
m = 1;
eqn = @(r,t,T,dudx)heatcondPDE(r,t,T,dudx,C);
ic = @(r)heatcondPDE_IC(r,C);
bc = @(rl,Tl,rr,Tr,t)heatcondPDE_BC(rl,Tl,rr,Tr,t,C);
sol = pdepe(m,eqn,ic,bc,r,t);
T = sol(:,:,1);
plot(r,[T(1,:);T(5,:);T(10,:);T(20,:);T(30,:);T(40,:);T(80,:)])
grid on
function T0 = heatcondPDE_IC(r,C)
if r == C.ri
T0 = C.Ti;
else
T0 = C.T0;
end
end
function [c, f, s] = heatcondPDE(r,t,T,dudx,C)
c = 1;
f = C.alpha *dudx;
s = 0;
end
function [pl,ql,pr,qr] = heatcondPDE_BC(rl,Tl,rr,Tr,t,C)
pl = Tl - C.Ti;
ql = 0;
pr = 0;
qr = 1;
end

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