Inverse of a matrix

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L'O.G.
L'O.G. il 16 Mag 2023
Modificato: Matt J il 16 Mag 2023
I want to solve the following for X2: A = B(X1+X2) where B is a matrix, and A, X1, and X2 are vectors. I can't divide by a matrix. So I believe I take the inverse. Is that right? What is the best way of doing this with very large matrices?
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Matt J
Matt J il 16 Mag 2023
We would have to know what "very large" means to you.

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Matt J
Matt J il 16 Mag 2023
Modificato: Matt J il 16 Mag 2023
Ran in:
%Fake input data
B=rand(100); X1=rand(100,1); X2=rand(100,1);
A=B*(X1+X2);
%Now invert
X2_recovered=B\(A-B*X1);
norm(X2-X2_recovered) %Check discrepancy - should be small
ans = 4.4786e-13

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