see i am executing the code below

close all;
clear all;
clc;
str=('ttttttPttttPPttt');
length=numel(str);
aa=estring(str)
zz=numel(aa)
comp_ratio=length/zz

------function estring-----------
function  y = estring(str)
len = numel(str);
i = 0;
count = zeros(1,len);
y=[];
while( i<len )
  j=0;
  count(i+1) = 1;
  while( true )
      j = j + 1;
      if( i+j+1 > len )
          break;
      end
      if( str(i+j+1)==str(i+1) )
          count(i+1) = count(i+1) + 1;
      else
          break;
      end
  end
    if( count(i+1)==1 )
        a=str(i+1);
        length(a);
        y = [y a];
        i = i + 1;
    else
        a=str(i+1);
        b=count(i+1);
        y =[y a num2str(b)];
        i = i + b;
    end
end
end

I WANT TO KNOW THAT LENGTH/ZZ IS ACTUALLY CALCULATING COMPRESSION RATIO OR MY ASSUMPTION IS WRONG

Answer 1

[Geoff Hayes]

Tina - length is a built-in MATLAB function so please don't use this as a variable name.

As for calculating the data compression ratio, your code seems appropriate. You have divided the uncompressed size by the compressed size which is similar to the same equation found elsewhere.

[tina jain]

OK thank you Geoff Hayes