我想知道为啥MATLAB的2阶和3阶为啥一样,谢谢!
程序:
>> syms z;
>> f=taylor(1/((1+z^2)^2),z)
>> f=taylor(1/((1+z^2)^2),z,'order',3)
>> f=taylor(1/((1+z^2)^2),z,'order',4)

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1,3、4阶泰勒级数一样,是因为没有z^3得项;
2,也可以用matlab验证你图片的。
simplify(-diff(taylor(1/(1+z^2),z,'order',7))/2/z)
ans =3*z^4 - 2*z^2 + 1

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