Plotting using given coordinates

The x,y cooridnates are given in below matrix:

Nodes_stacked = [

6.3480 3.6650;

0 7.3300;

-6.3480 3.6650;

-6.3480 -3.6650;

0 -7.3300;

6.3480 -3.6650;

12.6960 14.6600;

6.3480 18.3250;

0 14.6600;

0 7.3300;

6.3480 3.6650;

12.6960 7.3300

];

However i used the following code to plot, but the hexagons arent getting closed up.Any remedy?

% Extract x and y coordinates
x = Nodes_stacked(:, 1);
y = Nodes_stacked(:, 2);

% Plot the coordinates and connect them with lines
plot(x, y, 'o-');
xlabel('X Coordinates');
ylabel('Y Coordinates');
title('Plot of Coordinates');

Answer 1

[Dyuman Joshi]

The order of indices is not correct. I have corrected it -

Edit - Updated answer below for a bigger data set of points

%Modified array
Nodes_stacked = [
    6.3480    3.6650;
    0         7.3300;
    -6.3480    3.6650;
    -6.3480   -3.6650;
    0        -7.3300;
    6.3480   -3.6650;
    6.3480    3.6650;
    12.6960    7.3300;
    12.6960   14.6600;
    6.3480   18.3250;
    0        14.6600;
    0        7.3300;
    6.3480    3.6650;
    ];
%The last point in the array is redundant, you can remove it

% Extract x and y coordinates
x = Nodes_stacked(:, 1);
y = Nodes_stacked(:, 2);
plot(x, y, 'o-');
xlabel('X Coordinates');
ylabel('Y Coordinates');
title('Plot of Coordinates');

[Nupur]

Thanks a lot

[Nupur]

However i have a bigger matrix as below, then how to do?

https://docs.google.com/spreadsheets/d/1fewSBJGdx1pcMChLKCakmfdXTqZ72pSx73HCgnfcMoE/edit#gid=0

[Dyuman Joshi]

Is there any significance of values of Node Number 1 and Node Number 2?

[Nupur]

I didnt understand your statement.

If you are asking about the nodes, then Node 2 is next to Node 1. Node 3 is next to Node 2 and so on. all the coorindtes are in sequence.

[Dyuman Joshi]

@Nupur I was asking about the significane of two columns mentioned in the excel file named 'Node Number 1' and 'Node Number 2'.

They are indeed useful -

%The coordinates of points
vertices = [6.348	3.665
0	7.33
-6.348	3.665
-6.348	-3.665
0	-7.33
6.348	-3.665
12.696	14.66
6.348	18.325
0	14.66
12.696	7.33
6.348	25.655
0	29.32
-6.348	25.655
-6.348	18.325
12.696	36.65
6.348	40.315
0	36.65
12.696	29.32
6.348	47.645
0	51.31
-6.348	47.645
-6.348	40.315
12.696	58.64
6.348	62.305
0	58.64
12.696	51.31
6.348	69.635
0	73.3
-6.348	69.635
-6.348	62.305
12.696	80.63
6.348	84.295
0	80.63
12.696	73.3
19.043	3.665
12.696	-7.33
19.043	-3.665
25.391	14.66
19.043	18.325
25.391	7.33
19.043	25.655
25.391	36.65
19.043	40.315
25.391	29.32
19.043	47.645
25.391	58.64
19.043	62.305
25.391	51.31
19.043	69.635
25.391	80.63
19.043	84.295
25.391	73.3
31.739	3.665
25.391	-7.33
31.739	-3.665
38.087	14.66
31.739	18.325
38.087	7.33
31.739	25.655
38.087	36.65
31.739	40.315
38.087	29.32
31.739	47.645
38.087	58.64
31.739	62.305
38.087	51.31
31.739	69.635
38.087	80.63
31.739	84.295
38.087	73.3
44.434	3.665
38.087	-7.33
44.434	-3.665
50.782	14.66
44.434	18.325
50.782	7.33
44.434	25.655
50.782	36.65
44.434	40.315
50.782	29.32
44.434	47.645
50.782	58.64
44.434	62.305
50.782	51.31
44.434	69.635
50.782	80.63
44.434	84.295
50.782	73.3
57.13	3.665
50.782	-7.33
57.13	-3.665
63.478	14.66
57.13	18.325
63.478	7.33
57.13	25.655
63.478	36.65
57.13	40.315
63.478	29.32
57.13	47.645
63.478	58.64
57.13	62.305
63.478	51.31
57.13	69.635
63.478	80.63
57.13	84.295
63.478	73.3
69.826	3.665
63.478	-7.33
69.826	-3.665
76.173	14.66
69.826	18.325
76.173	7.33
69.826	25.655
76.173	36.65
69.826	40.315
76.173	29.32
69.826	47.645
76.173	58.64
69.826	62.305
76.173	51.31
69.826	69.635
76.173	80.63
69.826	84.295
76.173	73.3
82.521	3.665
76.173	-7.33
82.521	-3.665
88.869	14.66
82.521	18.325
88.869	7.33
82.521	25.655
88.869	36.65
82.521	40.315
88.869	29.32
82.521	47.645
88.869	58.64
82.521	62.305
88.869	51.31
82.521	69.635
88.869	80.63
82.521	84.295
88.869	73.3
95.217	3.665
88.869	-7.33
95.217	-3.665
101.564	14.66
95.217	18.325
101.564	7.33
95.217	25.655
101.564	36.65
95.217	40.315
101.564	29.32
95.217	47.645
101.564	58.64
95.217	62.305
101.564	51.31
95.217	69.635
101.564	80.63
95.217	84.295
101.564	73.3];

%Array comprising the values of Node numbers as columns
faces = [1	2
2	3
3	4
4	5
5	6
1	6
7	8
8	9
2	9
1	10
7	10
11	12
12	13
13	14
9	14
8	11
15	16
16	17
12	17
11	18
15	18
19	20
20	21
21	22
17	22
16	19
23	24
24	25
20	25
19	26
23	26
27	28
28	29
29	30
25	30
24	27
31	32
32	33
28	33
27	34
31	34
10	35
6	36
36	37
35	37
38	39
7	39
35	40
38	40
18	41
39	41
42	43
15	43
41	44
42	44
26	45
43	45
46	47
23	47
45	48
46	48
34	49
47	49
50	51
31	51
49	52
50	52
40	53
37	54
54	55
53	55
56	57
38	57
53	58
56	58
44	59
57	59
60	61
42	61
59	62
60	62
48	63
61	63
64	65
46	65
63	66
64	66
52	67
65	67
68	69
50	69
67	70
68	70
58	71
55	72
72	73
71	73
74	75
56	75
71	76
74	76
62	77
75	77
78	79
60	79
77	80
78	80
66	81
79	81
82	83
64	83
81	84
82	84
70	85
83	85
86	87
68	87
85	88
86	88
76	89
73	90
90	91
89	91
92	93
74	93
89	94
92	94
80	95
93	95
96	97
78	97
95	98
96	98
84	99
97	99
100	101
82	101
99	102
100	102
88	103
101	103
104	105
86	105
103	106
104	106
94	107
91	108
108	109
107	109
110	111
92	111
107	112
110	112
98	113
111	113
114	115
96	115
113	116
114	116
102	117
115	117
118	119
100	119
117	120
118	120
106	121
119	121
122	123
104	123
121	124
122	124
112	125
109	126
126	127
125	127
128	129
110	129
125	130
128	130
116	131
129	131
132	133
114	133
131	134
132	134
120	135
133	135
136	137
118	137
135	138
136	138
124	139
137	139
140	141
122	141
139	142
140	142
130	143
127	144
144	145
143	145
146	147
128	147
143	148
146	148
134	149
147	149
150	151
132	151
149	152
150	152
138	153
151	153
154	155
136	155
153	156
154	156
142	157
155	157
158	159
140	159
157	160
158	160];


%Using patch() with data
patch('Faces', faces, 'Vertices', vertices)

Answer 2

[Steven Lord]

Are all the nodes the same distance from the center of your hexagon at (0, 0)?

Nodes_stacked = [
    6.3480    3.6650;
    0         7.3300;
   -6.3480    3.6650;
   -6.3480   -3.6650;
    0        -7.3300;
    6.3480   -3.6650;
   12.6960   14.6600;
    6.3480   18.3250;
    0        14.6600;
    0        7.3300;
    6.3480    3.6650;
   12.6960    7.3300
];
N = vecnorm(Nodes_stacked, 2, 2)

N = 12×1

7.3300 7.3300 7.3300 7.3300 7.3300 7.3300 19.3934 19.3934 14.6600 7.3300

Okay, so the first few points (with radius around 7.33) are the lower-left hexagon and the others are for the upper-right hexagon? Let's see if we can recreate that first hexagon a different way, using a regular six-sided polygon.

R = N(1);
P = nsidedpoly(6, 'Radius', R);

Does this look similar to your lower-left hexagon?

plot(P)
axis([-10 15 -10 20])

No, but it looks like a rotated version. Let's rotate it by 30 degrees and see if it looks closer to what you showed.

P2 = rotate(P, 30);
figure
plot(P2)
axis([-10 15 -10 20])

That does. What does making this a polyshape object get us? We can rotate it with the rotate function, make copies by translating it, and do other transformations to it. See the polyshape documentation page and look at the list of "Object Functions" for more capabilities you can use to manipulate those objects.

P3 = translate(P2, [0 2*R]); % Make a copy of P2 with its center at (0, 2*R) instead of (0, 0)
figure
plot(P2) % The original
hold on
plot(P3, 'FaceColor', 'r') % The copy
axis equal

Now I could create an array [P2, P3] and translate both in one call to translate.

If you want the coordinates, you can ask for the Vertices property of the object.

coordinates = P2.Vertices

coordinates = 6×2

0 -7.3300 -6.3480 -3.6650 -6.3480 3.6650 0 7.3300 6.3480 3.6650 6.3480 -3.6650

Those numbers look close to the entries in Nodes_stacked, albeit in a slightly different order.

[Nupur]

This is also an approach, however the way they are sharing the vertex is wrong. They should share side and not just one vertex.

[Steven Lord]

This was just intended to demonstrate how to translate a polyshape. You could adjust the offset to translate it differently.

[Nupur]

But i actually cannot understand how this translation will help in plotting?

[Nupur]

This translation , i have tied before for unit hexagons

[Nupur]

I have all the coordinates of the nodes in a matrix, as shared in above excell sheet. Now i need to mark them and form a closed structre.