# Arrays have incompatible sizes for this operation.

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Syazana il 1 Ago 2023
Commentato: Dyuman Joshi il 1 Ago 2023
Hello! I want to calculate the acceleration but there's error which is I don't know what's need to be amend .
All the array here have the same dimension which is 1x47
s2= sind([-23.155386 -23.124987 -23.104193 ...])
s3= sind([38.535091 39.562313 40.583305 ...])
c2=cosd([-23.155386 -23.124987 -23.104193 ...])
c3=cosd([ 38.535091 39.562313 40.583305 ...])
c4=cosd([86.32077 86.347443 86.42453 ...])
s4=sind([86.32077 86.347443 86.42453 ...])
s5=sind ([ -35.981091 -36.282097 -36.616375 ...])
c5=cosd([-35.981091 -36.282097 -36.616375 ...])
c6=cosd([-29.205807 -29.200783 -29.196812 ...])
s6=sind([-29.205807 -29.200783 -29.196812 ...])
c7=cosd([-37.455574 -37.206734 -36.926373 ...])
s7=sind([-37.455574 -37.206734 -36.926373 ...])
diff_q1t=[-0.752469036 -0.785655599 -0.821694903 ...])
diff_q2t=[0.057738982 0.04467432 0.024727825 ...])
diff_q3t=[1.798555686 1.787403904 1.77699127 ...])
diff_q4t=[-0.204530772 -0.170022994 -0.123331074 ...])
diff_q5t=[-0.441452236 -0.443240326 -0.451332545 ...])
diff_q6t=[-0.016948892 -0.003593633 0.004956735 ...])
diff_q7t=[0.349886155 0.354433611 0.363348752 ...])
diff_q1t_second_derivative = diff(diff_q1t)
% Time array
time = (-0.4:0.01:0.06)
% here is my equation for acceleration
NaAstar_a1 = ((pA.*(s3.*diff_q2t + c2.*c3.*diff_q1t) - pA.*(s2.*diff_q1t + diff_q3t)).*(s2.*diff_q1t + diff_q3t) - pA.*(c2.*s3.*diff_q1t_second_derivative - c3.*diff_q2t + s3.*diff_q3t.*diff_q2t + c2.*c3.*diff_q3t.*diff_q1t - s2.*s3.*diff_q2t.*diff_q1t) - pA.*(s2.*diff_q1t_second_derivative + c2.*diff_q2t.*diff_q1t + diff_q3t + (pA.*(s3.*diff_q2t + c2.*c3.*diff_q1t) - pA.*(c3.*diff_q2t - c2.*s3.*diff_q1t)).*(c3.*diff_q2t - c2.*s3.*diff_q1t)));
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Syazana il 1 Ago 2023
Oh ya sorry for misundertsanding, then how I can set the second derivate of diff_q1t to be the same array as diff_q1t? Is it true if I set like this since the -1.4454 is the min number in the diff_q1t
diff_q1t_second_derivative = diff([-1.4454 diff_q1t])
Dyuman Joshi il 1 Ago 2023
You can put any number there, but the final output value(s) will depend on the number.
You can also use gradient instead of diff

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