Azzera filtri
Azzera filtri

error to assign string in field struct's

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>> SlippSource(2)
ans =
categorical
From instrument
Sis(:).Slipp
ans =
'From strategy'
ans =
'From strategy'
ans =
'From strategy'
>> class(Sis)
ans =
'struct'
>> size(Sis)
ans =
1 73
>> [Sis.SlippSource]=SlippSource(2)
Error using ()
Too many output arguments.

Risposta accettata

Walter Roberson
Walter Roberson il 23 Set 2023
Compare:
Sis(73).Slipp = 'example';
[Sis.SlippSource] = testfun();
Error using solution>testfun
Too many output arguments.
function output = testfun()
output = 123;
end
  2 Commenti
Walter Roberson
Walter Roberson il 23 Set 2023
Sis(73).Slipp = 'example';
[Sis.SlippSource] = deal(testfun());
whos Sis
Name Size Bytes Class Attributes Sis 1x73 8998 struct
function output = testfun()
output = 123;
end
Your Sis is a 1 x 73 struct. When you use [Sis.SlippSource] = SlippSource(2) then SlippSource(2) would have to be an expression that returns at least 73 output arguments.
Remember, when you have a non-scalar struct A then [A.B]=C is equivalent to coding [A(1).B, A(2).B, A(3).B, ... A(end).B] = C; which requires that C has enough outputs.
If you want to assign the same value to a particular field in each entry in the struct, then use deal like I show here.
piero
piero il 24 Set 2023
thanks..I didn't remember the word "deal"

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