Azzera filtri
Azzera filtri

indexing in the nested loop

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Raushan
Raushan il 4 Ott 2023
Commentato: Raushan il 4 Ott 2023
sum_y_2_s=0;
sum_x_2_s=0;
for s=0:1:T-1
sum_y_2_s(s)=sum_y_2_s;
sum_x_2_s(s)=sum_x_2_s;
for z=s:1:T-1
sum_y_2_s(s)=sum_y_2_s(s)+y.^(z-s);
sum_x_2_s(s)=sum_x_2_s(s)+x.^(z-s);
ratio_1=(sum_y_2_s(s)./(sum_x_2_s(s)+K^(1/gamma)*x.^(T-s)));
end
if ratio_1<1
s_asterisk=s(end);
return
end
end
How should I index loop correctly. It shows
Array indices must be positive integers or logical values.
Error in opt_ret_positive_wealth (line 18)
sum_y_2_s(s)=sum_y_2_s
I am trying to find this ratio.
Thank you very much

Risposta accettata

Torsten
Torsten il 4 Ott 2023
Modificato: Torsten il 4 Ott 2023
sx = 0;
sy = 0;
for s = T-1:-1:0
sx = sx + x^(T-1-s);
sy = sy + y^(T-1-s);
ratio(s+1) = sy/(sx+K^(1/gamma)*x^(T-s));
end
  3 Commenti
Torsten
Torsten il 4 Ott 2023
The answer has changed. If x or y equal 1, you get a division by zero from the old code. The code above should cover all possible cases for x,y > 0. You should compare the results from both codes.
Raushan
Raushan il 4 Ott 2023
I got you, thank you

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