solving integral with three parameters

Hello everyone. I have question about parametric integral. I need to find the x and y when teta is especific values like 0.5, 1,2...

clc;clear;

H = 50;

z = H/2;

Z = z/H;

Pe = 4;

syms x y Z_p

R_p = ((x^2 + y^2)^0.5)/H;

R = sqrt(R_p^2 + (Z - Z_p)^2);

f = (1/R) * exp (Pe * R/2);

teta = exp(Pe/2*R_p*cos(phi)*(int(f,Z_p,[0 1]-int(f,Z_p,[-1 0])

• phi is polar angle from 0 to pi. for this step lets imagine 0.
• The results should be pair of x and y that if we plot them will be oval it circular shapes.

[Rik]

What have you tried so far?

[Saeid Bina]

Thank you so much for your reply. I firstly tried without the first part but does not work again.

clc;clear;

syms x y Z_p

H = 50;

z = H/2;

Z = z/H;

Pe = 4;

R_p = ((x^2 + y^2)^0.5)/50;

R = sqrt(R_p^2 + (Z - Z_p)^2);

f = (1/R) * exp (Pe * R/2)

solve(int(f,Z_p,[0 1])==2)

I deleted the first part.