Adding specified loop outputs

3 visualizzazioni (ultimi 30 giorni)
S
S il 28 Mar 2024
Commentato: S il 11 Apr 2024
I am trying to make a figure which plots the sum of 3 specific loop outputs. output is the different outputs of the loop and I am trying to get the sum of output 1, 2, and 3. This is what I have:
figure
Sum1=sum(output(1:3));
plot(t,Sum1)
But I am just getting a blank graph and Sum1 for some reason has a value of 0 in my workplace. I am not sure which part of what I am doing is incorrect. Thank you for your time!
  4 Commenti
S
S il 30 Mar 2024
>> size(output)
ans =
5 2000
Torsten
Torsten il 30 Mar 2024
Modificato: Torsten il 30 Mar 2024
Example:
output = rand(5,2000)
output = 5×2000
0.0093 0.4352 0.6442 0.8223 0.0669 0.0750 0.1579 0.4659 0.4245 0.6393 0.5641 0.4505 0.4841 0.5146 0.3356 0.3269 0.7271 0.9070 0.5396 0.0868 0.7764 0.3069 0.7120 0.8052 0.9633 0.6658 0.3569 0.1724 0.1989 0.1068 0.5921 0.7917 0.6307 0.8559 0.3566 0.4708 0.3033 0.5932 0.8028 0.4506 0.3292 0.9448 0.2092 0.5576 0.1514 0.5201 0.8899 0.5369 0.4797 0.8613 0.6280 0.1493 0.3335 0.0613 0.5330 0.3729 0.5056 0.2013 0.3167 0.1885 0.0947 0.8074 0.7094 0.3982 0.4959 0.4298 0.9395 0.8940 0.6521 0.5169 0.6788 0.1383 0.9413 0.5478 0.0879 0.6249 0.1888 0.8520 0.4720 0.5320 0.0991 0.5874 0.9938 0.3726 0.8688 0.4819 0.6446 0.2709 0.1690 0.0696 0.7237 0.6625 0.5572 0.2795 0.1393 0.5328 0.8897 0.1949 0.1757 0.2561 0.0574 0.4576 0.8966 0.7007 0.4071 0.4533 0.5061 0.2979 0.8647 0.7720 0.0163 0.8398 0.7416 0.2130 0.3288 0.0865 0.1613 0.2869 0.6096 0.1663 0.8057 0.2727 0.5270 0.3867 0.4939 0.0631 0.1537 0.0135 0.6568 0.6885 0.1418 0.0855 0.8256 0.8523 0.3056 0.7419 0.5254 0.7348 0.0874 0.6650 0.5307 0.6938 0.7397 0.1528 0.8003 0.1851 0.3351 0.1735 0.0691 0.5860
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output(1:3)
ans = 1×3
0.0093 0.5921 0.0947
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Sum1=sum(output(1:3))
Sum1 = 0.6961
Thus you try to plot one single value (which seems to be 0 in your case).

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Risposta accettata

Mathieu NOE
Mathieu NOE il 2 Apr 2024
hello again
seems to me you want to sum the first 3 rows so
it should be :
Sum1=sum(output(1:3,:)); instead of Sum1=sum(output(1:3));
output = rand(5,2000)
output = 5x2000
0.1791 0.8425 0.6411 0.9862 0.3772 0.5695 0.0062 0.4191 0.0342 0.4738 0.1301 0.5518 0.6119 0.1510 0.9088 0.5260 0.4196 0.2989 0.1783 0.3134 0.7180 0.3725 0.1104 0.1097 0.2979 0.1851 0.7062 0.0656 0.1199 0.9486 0.5756 0.5375 0.3127 0.3970 0.1694 0.3851 0.8991 0.5512 0.2973 0.0736 0.0879 0.9771 0.1746 0.9450 0.8210 0.4277 0.6274 0.3267 0.7170 0.9286 0.1474 0.6039 0.4600 0.6433 0.4516 0.5993 0.9955 0.5155 0.3603 0.3852 0.1793 0.2607 0.9741 0.4219 0.0558 0.7762 0.7187 0.9905 0.8076 0.6963 0.0663 0.6098 0.1652 0.8677 0.4870 0.6077 0.4855 0.3860 0.0821 0.3845 0.3874 0.3454 0.6813 0.9306 0.7205 0.9261 0.8512 0.6857 0.4511 0.6153 0.8288 0.7844 0.1568 0.0911 0.2925 0.2977 0.1513 0.5298 0.4435 0.7714 0.5839 0.6496 0.3966 0.9823 0.9219 0.1772 0.1597 0.4256 0.9880 0.2713 0.7444 0.5459 0.4914 0.8019 0.6221 0.8412 0.1941 0.7266 0.0968 0.4999 0.9924 0.3889 0.5036 0.9485 0.9013 0.6529 0.4048 0.1062 0.2379 0.2751 0.9468 0.3906 0.3642 0.5598 0.9254 0.3007 0.4848 0.8409 0.0269 0.0066 0.3663 0.7956 0.3960 0.0903 0.1309 0.7850 0.9601 0.3460 0.0059 0.7290
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Sum1=sum(output(1:3,:))
Sum1 = 1x2000
0.9340 1.6407 1.9280 1.8050 0.6024 1.7308 1.6240 1.9609 1.1390 1.2437 0.2843 2.1387 0.9517 1.9636 2.2169 1.5615 1.5326 1.0116 0.9774 1.6264 1.2528 1.3218 1.2517 1.6836 1.4700 1.7104 2.5530 1.2668 0.9312 1.9491
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plot(Sum1)
  3 Commenti
Stephen23
Stephen23 il 9 Apr 2024
"So this works great until I use any number above 5 as start or finish then I get: Index in position 1 exceeds array bounds. Index must not exceed 5."
Of course you will get that error: if you matrix only has five rows (as with the example give by Mathieu NOE) then what do you expect MATLAB to do when you try to access a non-existent sixth row? Or for that matter, any other row that does not exist.
S
S il 11 Apr 2024
@Stephen23 there are 32 rows

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