Simple For Loop To Find Indices

1 visualizzazione (ultimi 30 giorni)
Melissa
Melissa il 20 Apr 2015
Modificato: Guillaume il 20 Apr 2015
Hello.
I have a question about a simple for loop. I have an original latlon set of about 500x1 unique coordinates. I have a subset of that latlon set in which I would like to find the indices for. So I have created a for loop to try to find it.
indices = zeros(length(subset),1); %create matrix of zeros to fill
for ii=1:length(subset);
indices(ii) = find(original==subset(ii));
end
But I keep getting: Subscripted assignment dimension mismatch. What am I doing wrong? In the end I want a matrix the size of the subset to indicate which indices are correlated to my latlon subset in relation to my original latlon.
Thank you,
Melissa

Risposta accettata

Guillaume
Guillaume il 20 Apr 2015
Modificato: Guillaume il 20 Apr 2015
The only way you can get this error with the code you've presented is if is find returns strictly less or more than one element, that is either the element of your subset is not found, or it is found more than once (i.e. your original array is not unique).
In any case, the loop is not needed there are set functions already present in matlab to do what you want. In your case, it's simply:
[~, indices] = ismember(subset, original)

Più risposte (1)

Hikaru
Hikaru il 20 Apr 2015
Modificato: Hikaru il 20 Apr 2015
Are your variables stored as double, or cells?
edit: I'm sorry. I made a mistake and I removed the incorrect statement.
  2 Commenti
Melissa
Melissa il 20 Apr 2015
Hi Hikaru,
They're stored as double. So how should I modify it so that I am not comparing a whole vector to one value? Do I add another loop inside of that loop?
Hikaru
Hikaru il 20 Apr 2015
I tried your code using a smaller sized variables,
original = [60; 40; 100; 120];
subset = [120; 40; 60];
indices = zeros(length(subset),1);
for ii=1:length(subset);
indices(ii) = find(original==subset(ii))
end
and it works okay as long as the values in subset can also be found in the original vector.
I'm not sure why you got that error without looking at the sample matrix, but have you check if there are same values in the original vector?

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by