peak value at the centre of F(0,0) in magnitude plot of fourier transform
Mostra commenti meno recenti
According to this doc
consists of a single line when Im using this
FT=fft2(linkImage);
freqz(linkImage)
In the doc it is mentioned that the center at F(0,0)of fourier tarnsform contains sum of all values in FT.But in my image along with the centre peak two more peaks are visible.Can someone explain what are they.
2 Commenti
Wayne King
il 16 Nov 2011
Hi, I don't see how you are calling freqz() on an image.
freqz() expects two input vectors, or is this not a MATHWORKS' freqz?
Gova ReDDy
il 16 Nov 2011
Risposta accettata
Più risposte (5)
Wayne King
il 16 Nov 2011
At any rate, I think only when you shift the 2-D Fourier transform does it end up in the middle. Note that:
rng default;
x = randn(20,20);
xdft2 = fft2(x);
sum(x(:))
xdft2(1,1)
Now
xdft2 = fftshift(xdft2);
xdft2(11,11)
Wayne King
il 17 Nov 2011
You wrote freqz() above. freqz2() is for a filter.
For example:
h = 0.01*ones(10,10);
sum(h(:))
H = freqz2(h,10,10);
H(6,6)
3 Commenti
Gova ReDDy
il 17 Nov 2011
Wayne King
il 17 Nov 2011
freqz2() is for a 2-D FIR filter, freqz() handles both FIR and IIR filters. You can infer the frequency response for your 2-D FIR filter from the 1-D response with freqz() iff your 2-D FIR filter is separable, but I wouldn't assume that this always the case.
Gova ReDDy
il 22 Nov 2011
Image Analyst
il 22 Nov 2011
0 voti
Come on, obviously "F(0,0)of Fourier transform contains sum of all values in FT" is NOT CORRECT. It simply can't be (unless your FT is a delta function) - just think about it for half a second. The F(0,0) element is the "DC component" as it is often called and is proportional to the mean of the spatial domain image. Go back and read the documentation and you'll see that it really says "Note that F(0,0) is the sum of all the values of f(m,n)." Note that f is the spatial domain image, not the Fourier Transform! The sum of all the values of the image is, of course, proportional to the mean of the image.
Gova ReDDy
il 23 Nov 2011
0 voti
2 Commenti
Walter Roberson
il 23 Nov 2011
Frequency is encoded by position, not by value.
Gova ReDDy
il 23 Nov 2011
umar siyab
il 24 Nov 2011
0 voti
when u want to centre the image u must use the fftshift function afterall your image will center at f(0,0)... the f(0,0) will contain the lowest values of pixel as compared to move from centre
Categorie
Scopri di più su Filter Analysis in Centro assistenza e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!