how to replace double vectors from 0 to '000'

hello every body; i am dealing with string and number how i can solve this problem: "In an assignment A(I) = B, the number of elements in B and I must be the same." "E_extrac_pro(ex_loop2)='000';" where numbers vector are double and contains:

numbers=[202;0 ;20;0;0;1013;10];

for ex_loop2=1:size(numbers)
    if(numbers(ex_loop2)==0)
        E_extrac_pro(ex_loop2)='000';
    else
        E_extrac_pro(ex_loop2)=numbers(ex_loop2);
    end
end

Answer 1

[Stephen23]

Why bother with the loop at all?:

>> numbers=[202;0 ;20;0;0;1013;10];
>> X = num2str(numbers,'%04g')
X =
0202
0000
0020
0000
0000
1013
0010

And if the output must be a cell array:

>> cellstr(X)
ans = 
  '0202'
  '0000'
  '0020'
  '0000'
  '0000'
  '1013'
  '0010'

[Mohamuud hassan]

thank you stephen, but the output that i estimating is not:

0202
0000
0020
0000
0000
1013
0010
but it will be:

 202
 000
 020
 000
 000
 1013
 010

[Stephen23]

Then you can adjust the format string to get the desired result:

>> X = num2str(numbers,'%03g')
X =
 202
 000
 020
 000
 000
1013
 010
>> strtrim(cellstr(X))
ans = 
  '202'
  '000'
  '020'
  '000'
  '000'
  '1013'
  '010'

The num2str documentation clearly explains these formatting options. Or you could put it in an arrayfun with sprintf:

>> arrayfun(@(n)sprintf('%03g',n), numbers, 'UniformOutput',false)
ans = 
  '202'
  '000'
  '020'
  '000'
  '000'
  '1013'
  '010'

[Mohamuud hassan]

thank you stephen.

Answer 2

[Image Analyst]

To mix strings and numbers in the same array, you'll have to use a cell array:

E_extrac_pro = cell(1, size(numbers));
for ex_loop2=1:size(numbers)
    if(numbers(ex_loop2)==0)
        E_extrac_pro{ex_loop2}='000';
    else
        E_extrac_pro{ex_loop2}=numbers(ex_loop2);
    end
end

For more info, see FAQ: What is a cell array

[Mohamuud hassan]

i applied your idea but with new error: Cell contents assignment to a non-cell array object. E_extrac_pro{ex_loop2}=numbers(ex_loop2);