Conveter a string with space in a number
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A have one vector returned by the function textscan which have spaces inside the numerical string.
E.g.:
' 0 0 , 2 3 '
' 1 2 , 1 5 '
First, a have to substitute the ',' by '.' (it's simple) but how I remove the spaces? Because using str2num in this vector is returned error.
2 Commenti
Stephen23
il 26 Ago 2020
Modificato: Stephen23
il 26 Ago 2020
"A have one vector returned by the function textscan which have spaces inside the numerical string."
I am surprised that no one brought up the obvious solution, to fix the (likely) problem at its source by handling the file encoding properly. Then textscan would import the data correctly.
Image Analyst
il 26 Ago 2020
Well, someone might have, but the original poster forgot to attach the original text file. That is a common omission. For some reason, many/most posters totally ignore the posting guidelines that they are shown when they post the question, one of which says to attach their data.
Risposta accettata
Image Analyst
il 20 Giu 2015
It's pretty much the same except that you set it equal to [] instead of a decimal point:
str(str == ' ') = []; % Remove spaces
3 Commenti
Walter Roberson
il 20 Giu 2015
cellfun(@(str)str(str~=' '), dataArray, 'Uniform', 0)
Walter Roberson
il 20 Giu 2015
cellfun(@(str)str(2:2:end), dataArray, 'Uniform', 0)
in the case where the odd-numbered characters are the blanks.
Più risposte (1)
Azzi Abdelmalek
il 20 Giu 2015
Modificato: Azzi Abdelmalek
il 20 Giu 2015
s={' 0 0 , 2 3 ';'1 2 , 1 5 '}
a=strrep(s,',','.')
b=strrep(a,' ','')
out=str2double(b)
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