Why is the if statement not working?
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
this is my code - it is supposed to be a binary array, where the length of time (through the array) that the "1"s are held is determined by "time" - why is the if statement not working based off of the output of "time"?
function cube=cube(exp)
exp=zeros(60,96,10);
time=randi([3 7]);
if time==3
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 8]);
exp(j,jj,rand:rand+2)=1;
end
end
elseif time == 4
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 7]);
exp(j,jj,rand:rand+3)=1;
end
end
elseif time == 5
for j=1:s ize(exp,1);
for jj=1:size(exp,2);
rand=randi([1 6]);
exp(j,jj,rand:rand+4)=1;
end
end
elseif time == 6
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 5]);
exp(j,jj,rand:rand+5)=1;
end
end
elseif time == 7
for j=1:size(exp,1);
for jj=1:size(exp,2);
rand=randi([1 4]);
exp(j,jj,rand:rand+6)=1;
end
end
cube=exp
end
1 Commento
the cyclist
il 3 Ago 2015
One suggestion, aside from trying to solve your main problem, is that you should not be using MATLAB keywords as variable names, because the code may behave in unexpected ways, and also the code simply becomes very confusing (especially for veteran users). In your case, exp and rand should be avoided as variable names.
Risposta accettata
the cyclist
il 3 Ago 2015
One problem is that in the elseif statement where you check if time == 5, you have
for j=1:s ize(exp,1);
instead of
for j=1:size(exp,1);
0 Commenti
Più risposte (1)
the cyclist
il 3 Ago 2015
Modificato: the cyclist
il 3 Ago 2015
You need
time==3
instead of
time=3
== is the "determine equality" operator. = is the assignment statement.
Vedere anche
Categorie
Scopri di più su Startup and Shutdown in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!