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how to do the distance transform

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Yu Zhang
Yu Zhang il 12 Dic 2011
Hi,all.I am processing a image. I need to do the distance transformation.This is my code:
myImage=imread('EarImage_1.tif');
I = rgb2gray(myImage);
whitePart = I > 220;
blackPart = I < 110;
imshow(whitePart);
I2=1-blackPart;
figure,imshow(I2);
D=bwdist(I2);
figure,imshow(~D);
This is my original picture:
After this process,I got an image just the same as "I2",which is the binary image before. I didn't get the picture as expected. I am a beginner of matlab. If anyone could tell me the solution of that, I would appreciate very much.
Thank you.
  1 Commento
Walter Roberson
Walter Roberson il 12 Dic 2011
http://www.mathworks.com/matlabcentral/answers/7924-where-can-i-upload-images-and-files-for-use-on-matlab-answers

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Sean de Wolski
Sean de Wolski il 12 Dic 2011
showing ~D means that only distances equal to zero (i.e. points that are true in I2) will be shown. D is an array of doubles.
imshow(D,[]);
will show you the distance xform image with the full range of values. Good job getting to where you are, +1.
  2 Commenti
Yu Zhang
Yu Zhang il 13 Dic 2011
Thank you very much! I got it. But the results look not good. I could not identify the kernel at all. Could you tell me whether I should do some other processes before the distance transform? I have done the median filter and get the gradient of the image. The gradient image looks good which is clear enough.Thank you!
Sean de Wolski
Sean de Wolski il 13 Dic 2011
We need to see your image. Post it somewhere, perhaps to one of the websites in Walter's comment link and paste the url into your original question.

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Walter Roberson
Walter Roberson il 12 Dic 2011
Do not subtract blackPart from 1 if you want to see white pixels for the locations selected by blackPart.
1-(I<110) is the same as (I>=110) which could look very similar to (I>220) that you are already plotting. All of the (I>220) would be included within the (I>=110)

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