How can I solve this error? "Subscripted assignment dimension mismatch"

clc;
close all;
clear all;

faceDatabase=imageSet('Database','recursive');

figure;
montage(faceDatabase(1).ImageLocation);
title('Images of single Face');
% DisplayQuery image n database...
    %personQuery=1;
    %GImage=read(faceDatabase(personQuery),1);
    %for i=1:size(faceDatabase,2)

      %end
  %splitting
  [training,test]=partition(faceDatabase,[0.8,0.2]);

person=3;
[features,vis]=extractHOGFeatures(read(training(person),1));
figure;
subplot(2,1,1),imshow(read(training(person),1)),title('Input Face');
subplot(2,1,2),plot(vis),title('HOG features');

% extract HOG Features of all images
trainingF=zeros(size(training,2)*training(1).Count);
featurecount=1;

for i=1:size(training,2)
    for j=1:training(i).Count
        trainingF(featurecount,:)=extractHOGFeatures(read(training(i),j));
        trainingL{featurecount}=training(i):Description;
        featurecount=featurecount+1;
    end
    personI{i}=training(i).Description;
end

%%for descrimination of each images..
faceClassifier=fitcecoc(trainingF,trainingL);

person=1;
queryImage=read(test(person),1);
queryFeatures=extractHOGFeatures(queryImage);
personLabel=predict(faceClassifier,queryFeatures);

%map to traingset
        booleanIndex=strcmp(personLabel,personI);
        integerIndex=find(booleanIndex);
        subplot(1,2,1);
        imshow(queryImage),title('Query Face');
        subplot(1,2,2);
        imshow(read(training(integerIndex),1)),title('Matched Image');

[Walter Roberson]

You need to show us the exact error message indicating which line the problem is occurring on.

[Image Analyst]

Please read this now.

Answer 1

[Leandro Souza]

fix trainingF size

trainingF = zeros(size(training,2)*training(1).Count,size(feature,2));

[Saira]

How can I solve this error?

Error:

Subscripted assignment dimension mismatch

trainingL{featurecount}=training(i):Description;

Thanks

[Walter Roberson]

saira arshad

The : operator is a range construction operator, and is unlikely to be correct in this context.