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If loop using cell arrays

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Bas
Bas il 14 Set 2015
Commentato: Titus Edelhofer il 14 Set 2015
Hi,
I have 2 matrices:
A with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) defining salaries
B with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) contains either a 0 or a 1
And last I have 2 boundary values C= 2600 and D= 1700.
I want to check the following:
if B(each value) == 0 && A(each value) > C
A(this value)= C
elseif B(each value) == 1 && A(each value) > D
A(this value)= D
end
Can anyone help me out?
  1 Commento
Walter Roberson
Walter Roberson il 14 Set 2015
There is no such thing as an "if loop". There are "for loop" and there are "while loop" and there are "if statement". A loop would have to execute its body multiple times, but "if" executes the body only 1 time or 0 times.

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Risposta accettata

Guillaume
Guillaume il 14 Set 2015
You don't need any if. Just use logical operations. Your first condition is to replace elements when B is false (i.e. B==0 or simply ~B) and A greater than C, so is simply writen as A(~B & A>C). Similarly your second condition is simply A(B==1 & A>D) (which simplifies to A(B & A>D). You just have to apply that to each cell of the cell arrays:
for cellidx = 1:numel(A)
a = A{cellidx};
b = B{cellidx};
a(~b & a>C) = C;
a(b & a>D) = D;
A{celldix} = a;
end
  1 Commento
Bas
Bas il 14 Set 2015
Thanks Guillaume, this is what I was searching for!

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Più risposte (1)

Titus Edelhofer
Titus Edelhofer il 14 Set 2015
Hi,
I'm not 100% sure I understand what you want to do, but I guess it should be like this
for i=1:length(A)
if all(B{i}(:)==0 & A{i}(:)>C)
A{i}(:) = C;
elseif all(B{i}(:)==1 & A{i}(:)>D)
A{i}(:) = D;
end
end
Titus
  4 Commenti
Guillaume
Guillaume il 14 Set 2015
Modificato: Guillaume il 14 Set 2015
Both codes have the following preconditions:
assert(isequal(numel(A), numel(B)));
assert(all(cellfun(@(a,b) isequal(size(a), size(b)), A, B)));
Titus Edelhofer
Titus Edelhofer il 14 Set 2015
I wish I could vote for a comment! Nice assert calls.

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