How do I take specific data from an array?

6 visualizzazioni (ultimi 30 giorni)
I have 50 different on column vectors, each defined at t0 through t49. I need to be able to use the data at a certain point from each vector, but the problem is the data I want is not going to be in the same row for all 50 vectors. I want to tell it to start reading when t(i+1)<ti for every file but I'm not sure how to run a loop to do this 50 different times.
  2 Commenti
Kirby Fears
Kirby Fears il 18 Set 2015
Are these 50 column vectors already loaded into matlab memory? Are they 50 separate arrays, or is this a single table?
Kristen Brusich
Kristen Brusich il 18 Set 2015
they are 50 separate arrays already loaded into matlab

Accedi per commentare.

Risposta accettata

Kirby Fears
Kirby Fears il 18 Set 2015
Modificato: Kirby Fears il 18 Set 2015
For an Nx1 array V, you can contract V based on any conditional test such as the one you described. For example:
>> V=1:10;
>> V=V(V>5);
>> disp(V)
6 7 8 9 10
You should be able to use this kind of logic in a loop by applying your loop index.
  2 Commenti
Kristen Brusich
Kristen Brusich il 18 Set 2015
Okay, I understand that but now how do I make that into a for loop to run each manifold?
Kirby Fears
Kirby Fears il 18 Set 2015
Kristen,
I was going to ask for more information, but I see it's in your other question posted here.
I commented on your other question to help you get your vectors into a single cell. It's very easy to loop over a cell containing vectors to apply your logical statement to it.
C={1:10,1:20,1:7}; % sample cell of vectors
for iter=1:numel(C),
tempidx=C{iter}>5;
C{iter}=C{iter}(tempidx);
end,
Remember to accept my answer (and Walter's answer in your other post) if your questions have been answered.
Hope this helps.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by